Is anyone able to help please

Four friends all use $10 off coupons to buy themselves concert tickets.

eimsori [14]

Answer:

$64

Step-by-step explanation:

Since there were 4 of them and the coupons were $10 off, they saved a total of $40

To find how much they would have spent without the coupons, add 40 to 216:

216 + 40

= 256

To find the normal cost of one ticket, divide this by 4:

256/4

= 64

So, the price of one concert ticket without the coupon is $64

5 0

3 years ago

100 PTS:Please help me now plz plz

Alex Ar [27]

Answer:

x = 12

Step-by-step explanation:

We have a right triangle with hypotenuse 10 and the height 8. Either the one on the left or the one on the right

We can find the base using the Pythagorean theorem

a^2 + b^2 = c^2

a^2 +8^2 = 10^2

a^2 +64 = 100

Subtract 64 from each side

a^2 = 100 -64

a^2 = 36

Take the square root of each side

a = 6

Now a is 1/2 of the total base of the big triangle. It is identical since the triangles are equal

x = 2 * a

x = 2*6 = 12

4 0

2 years ago

Read 2 more answers

A cube has an edge measuring 4 inches what is the surface area of the cube in inches^2

Arada [10]

Answer:

96^2in

Step-by-step explanation:

4x4=16

16x6=96

5 0

2 years ago

Mr. Hong brought his 7 year-old daughter, Jin and his 10 year-old son, Cai, to Redwood Amusement Park. An Admission ticket coste

kompoz [17]

$20.25 because 8.50 and 8.50 equal 17 and then subtract 2.00 makes 15, and then add 5.25 and you end up with 20.25

4 0

3 years ago

A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p

gizmo_the_mogwai [7]

Answer:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

$\bar X_{1}=9.1$ represent the mean for the sample 1

$\bar X_{2}=8$ represent the mean for the sample 2

$s_{1}=1.9$ represent the sample standard deviation for the sample 1

$s_{2}=2.1$ represent the sample standard deviation for the sample 2

$n_{1}=40$ sample size for the group 1

$n_{2}=50$ sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis: $\mu_{1} = \mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

Statistical decision

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=40+50-2=88$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0

2 years ago