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2 years ago

Can someone give me a simple answer to this problem

Mathematics

1 answer:

Rashid [163]2 years ago

4 0

Where is it????????????????????

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The numbers in this sequence increase by the same amount each time.

PilotLPTM [1.2K]

Answer:

2, 4, 6, 8 , 10

Step-by-step explanation:

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2 years ago

Where are white blue and red boat in the Marina three fourths of the boats in the Marina are white for seventh of the remaining

xeze [42]

Answer:

Step-by-step explanation:

Here is the complete question used in answering this question :

Three-fourths of the boats in the marina are white. 4/7 of the remaining boats are blue , and the rest are red . If there are 9red boats, how many boats are in the marina?

We first have to determine the fraction of the boats that are red

1 - ( $\frac{3}{4}$ + $\frac{4}{7}$ )

1 - $\frac{21 + 16}{28}$

1 - $\frac{37}{28}$

1 - 1 $\frac{9}{28}$

= 9/28

so, 9/28 of the boats are red

let b represent the total number of boats

9/28 x b = 9

to find b, divide both sides of the equation by 28/9

b = 28

5 0

2 years ago

If f(x)=x sqrt -25 and g(x)=x-5, what is the domain of (f/g)(x)?

givi [52]

Answer:

Step-by-step explanation:

f(x)=x²-25=(x-5)(x+5)

g(x)=x-5

(f/g)(x)=<em>(x-5)</em>(x+5)/<em>(x-5)</em>=x+5; for x≠5

D=R-{5}

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2 years ago

Read 2 more answers

Solving Systems of linear equations by graphing. no graphing device.

valentina_108 [34]

Answer: (1,3)

Step-by-step explanation:

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2 years ago

A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is 11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

$\text{Area of painting}=l\times b$

$\text{Area of painting}=24\times 11$

$\text{Area of painting}=264 \text{ in}^2$

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

$\text{Area of painting with mat}=30\times 17$

$\text{Area of painting with mat}=510 \text{ in}^2$

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

$\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\$

$\text{Area of mat}=510-264$

$\text{Area of mat}=246 \text{ in}^2$

Hence, the area of the mat is 246 in².

6 0

2 years ago