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pychu [463]
2 years ago
11

Can someone give me a simple answer to this problem

Mathematics
1 answer:
Rashid [163]2 years ago
4 0
Where is it????????????????????
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garik1379 [7]
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3 years ago
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The radius of a sphere is increasing at a rate of 5 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 40 m
jeka94

9514 1404 393

Answer:

  8000π mm^3/s ≈ 25,133 mm^3/s

Step-by-step explanation:

The rate of change of volume is found by differentiating the volume formula with respect to time.

  V = 4/3πr^3

  V' = 4πr^2·r'

For the given numbers, this is ...

  V' = 4π(20 mm)^2·(5 mm/s) = 8000π mm^3/s ≈ 25,133 mm^3/s

_____

<em>Additional comment</em>

By comparing the derivative to the area formula for a sphere, you see that the rate of change of volume is the product of the area and the rate of change of radius. This sort of relationship will be seen for a number of different shapes.

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3 years ago
In a recipe for fizzy grape juice, the ratio of cups of sparkling water to cups of grape
Ierofanga [76]

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Step-by-step explanation: hold on let me think

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2 years ago
Lamont builds a triangular shape fence to hide his pool pump
Monica [59]
I don't understand what you are trying to say

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3 years ago
Factor the expression 20k + 50
Yuliya22 [10]
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
4 0
3 years ago
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