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pychu [463]
3 years ago
11

Can someone give me a simple answer to this problem

Mathematics
1 answer:
Rashid [163]3 years ago
4 0
Where is it????????????????????
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Simplify 2√2-√3<br> ---------------<br> √2+√3
serious [3.7K]

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

6 0
2 years ago
You spend 60 on clothes and buy 3 dvd movies. your friend spends nothing on clothes and buys 8 dvd movies. you both spend the sa
garik1379 [7]
Each dvd cost $7.50 how? Your friends buy 8 dvd's and in total is 60, you want to divide 60 from 8 and find that it's 7.50 and then multiply 8 to 7.50 and it should be 60. Hope this helps!!

5 0
3 years ago
Convert 5.45787878 to a fraction. Simplify
TiliK225 [7]

Answer:

It is 54033/9900

Step-by-step explanation:

7 0
3 years ago
I try to solve it but I didn't get any of the choices <br> Thank you for helping me
Natasha2012 [34]
The answer is 7. You can look at it like this. The two triangles are similar and the larger one's sides are twice the size of the smaller one's. So then we know GF is twice the size of JK.
2(2y+5)=5y+3
4y+10=5y+3
y=7
8 0
3 years ago
Guadalupe's credit card has an APR of 23% calculated on the previous monthly balance and a minimum payment of 2% starting the mo
Harman [31]
Answer: To find the finance charge you multiply the balance times 0.23 / 12 .

To find the interest charge to an account, you have to multiply the balance by the percent rate (APR). 

The problem in this case is that interest is charged monthly, but the rate is yearly.

To fix this problem, just divide the rate by 12.  
0.23 / 12 
8 0
3 years ago
Read 2 more answers
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