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wariber [46]
3 years ago
8

A sphere has been placed inside an cylinder with the same dimensions;both have a radius of 6cm,and a height of 12cm How many cub

ic centimeters of space does the sphere fill not fill up. A.432pi cm B.72 pi cm C.288 pi cm D.144 pi cm
Mathematics
1 answer:
monitta3 years ago
6 0

Answer:i think the answer is B?

Step-by-step explanation:

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Step-by-step explanation:

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The answer is 0.0136986301369863
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A rectangular prism has a volume of 42 cubic units. The length is 3 units. The width is 2 units. What is the height?
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3×2=6

42÷6=7

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A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea
marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that n = 11

Each question has five choices.

This means that p = \frac{1}{5} = 0.2

(a) Find P (6)

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859

P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362

P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953

P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389

Then

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611

P(More than 3) = 0.1611

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