A company's profit (in millions of dollars) can be represented by x^2-6x+12, where x is the number of years since the company st
1 answer:
The function that models the profit of the company in million of dollars is:
where x represents the number of years since the company started. We want to find when the profit of the company was $4 million. Setting P as 4 in above equation, we can find the value of x when the profit was $4 million.
Thus, we can conclude that the profit of the company was $4 million in 2nd and 4th year
where x represents the number of years since the company started. We want to find when the profit of the company was $4 million. Setting P as 4 in above equation, we can find the value of x when the profit was $4 million.
Thus, we can conclude that the profit of the company was $4 million in 2nd and 4th year
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so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2
answer is 336 m^2
so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2
answer is 336 m^2