If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
48, 53, 58, 63 is from low to hight numbers
Answer:
<u>-2</u>
Step-by-step explanation:
<u>Given</u> :
- An example of a coefficient ⇒ '11' in 11kk
<u>Solving</u> :
- The coefficient is the part that precedes the variable(s)
- Therefore, on solving -k - k
- ⇒ -2k
- ⇒ <u>-2 is the coefficient</u>
