What is the range of the function?
2 answers:
You might be interested in
Answer:
Solution,
base=1
perpendicular=?
hypotenuse=X
now,
using Pythagoras theorem,
x^2=p^2+b^2
or, x^2=p^2+1^2
or,p^2=x^2-1
or, p=√x^2-1
tan theta=perpendicular/ base
tan theta =√x^2-1/1
tan theta=√x^2-1
z=tan theta
z=√x^2-1
Hope this helps...
Good luck on your assignment..