The answer is angiosperm.
Angiosperms were the last plants to evolve. They spread during the Cretaceous period. The first fossils<span> of angiosperms are old about 135 million years. From this list, the first to evolve were a non-vascular plant, following by bryophyte, then gymnosperm, and angiosperm at the end.</span>
Rays of light that pass through the lens are brought closer together that’s because this lens is a converging lens.
Answer:
IBi and IBIB
Explanation:
Blood group in humans is determined by a single gene with three alleles (iA, iB and i). Alleles iA and iB are both dominant over i. This means that i allele will only be expressed in a homozygous state.
In the ABO blood group system, individuals will possess the following blood types when they possess the following genotypes:
Type A- iAiA or iAi
Type B- iBiB or iBi
Type O- ii
Alleles iA and iB are codominant, this means that they both phenotypically express themselves when combined as neither is dominant or recessive to the other. Hence, in an heterozygous state;
iAiB, the blood type of the individual will be Type AB.
Following this, Quincy with a type B blood will possess an allelic combination of iBiB (homozygous) or iBi (heterozygous) in her genotype.
Following the Hardy-Weinberg equilibrium theory, the frequency of the heter0zyg0us genotype is 2pq. In the exposed example, 2pq = 0.48.
<h3>
Hardy-Winberg equilibrium</h3>
The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q.
Assuming a diallelic gene,
→ The allelic frequencies are
- p is the frequency of the dominant allele,
- q is the frequency of the recessive allele.
→ The genotypic frequencies after one generation are
- p² (H0m0zyg0us dominant genotypic frequency),
- 2pq (Heter0zyg0us genotypic frequency),
- q² (H0m0zyg0us recessive genotypic frequency).
If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.
The addition of the allelic frequencies equals 1 ⇒ p + q = 1.
The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1
If the allele A has a frequency of 0.6, and the allele B has a frequency of 0.4, then the frequency of the heter0zyg0us genotype is
2pq = 2 x 0.6 x 0.4 =<u> 0.48</u>
You can learn more about the Hardy-Weinberg equilibrium at
brainly.com/question/3406634
The term that is used to describe the process of collecting a tissue sample from the endocervix is liquid-based Pap.
<h3>What is endocervix?</h3>
Endocervix is the inner part of the cervix which links the cervix to the uterus.
To examine the cellular structure of the endocervix, a pap smear examination is carried out.
When the pap smear is placed directly into a liquid fixative instead of being spread onto a glass slide it is called a liquid-based Pap.
Therefore, the term that is used to describe the process of collecting a tissue sample from the endocervix is liquid-based Pap.
Learn more about pap smear here:
brainly.com/question/1380012
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