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Olin [163]
3 years ago
12

WILL BE MARKED BRANLIEST: Activity

Mathematics
2 answers:
alisha [4.7K]3 years ago
4 0
4(12)+6= 54 that would be your answer
lisov135 [29]3 years ago
3 0

Answer:

54

Step-by-step explanation:

4x + 6 movies

12 movies,

x =12

4x + 6  for x= 12

4(12) + 6 = 54

You might be interested in
Which of the following terminating decimals is equivalent to Negative 1 and three-fourths?
Tems11 [23]

Answer:

-1.75

Step-by-step explanation:

This should be it, but you didn't provide options although you put "Which of the following.."

3 0
2 years ago
Read 2 more answers
Geometry Does a SSSS congruence relationship exist for parallelograms? If so explain why. If not, create a counter-example Geome
Lady_Fox [76]

We need to notice that SSSS does not exist as a method to prove that parallelograms are congruent

Counterexample

As we can see we have the same measure of the side of the intern angles of the figures are different therefore we can't use SSSS to prove congruence

3 0
9 months ago
If R is the set of all integers with absolute value less than 10, A is its subset containing all natural numbers less than 10 an
Elza [17]

Answer:

See explanation

Step-by-step explanation:

1. R is the set of all integers with absolute value less than 10, thus

R=\{a\in \mathbb{Z}\ :\ |a|

2. A is its subset containing all natural numbers less than 10, thus

A\subset R\\ \\A=\{b\in \mathbb{N}\ :\ b

3. B is the set of all integer solutions of inequality 2x+5<9 that are less than 10 by absolute value (and therefore, it is also a subset of R). First, solve the inequality:

2x+5

Thus,

B\subset R\\ \\B=\{c\in \mathbb{Z}\ :\ 2c+5

See the diagram in attached diagram.

Note that

A\cup B=R\\ \\A\cap B=\{1\}.

4 0
3 years ago
Use complete sentences to describe why √-1 ≠ -√1
tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>

\displaystyle \large{ {y}^{2}  = x} \\  \displaystyle \large{ y =  \pm  \sqrt{x} }

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{  {a}^{2}  = a \times a =  |b| }

Where b is the result from a×a. Let's see an example.

<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>

\displaystyle \large{  {2}^{2}  = 2 \times 2 = 4} \\  \displaystyle \large{  {( - 2)}^{2}  = ( - 2) \times ( - 2) =  | - 4|  = 4}

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

\displaystyle \large{   {y}^{2}  =  - 1}

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

\displaystyle \large{   \sqrt{ {y}^{2} } =   \sqrt{ - 1}  }

Then where does plus-minus come from? It comes from one of Absolute Value propety.

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>I</u>

\displaystyle \large{  \sqrt{ {x}^{2}  } =  |x|  }

Solving absolute value always gives the plus-minus. Therefore...

\displaystyle \large{  y =   \pm \sqrt{ - 1}  }

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

\displaystyle \large{   {y}^{2}  = 1} \\  \displaystyle \large{    \sqrt{ {y}^{2} }  =  \sqrt{1} } \\  \displaystyle \large{  y  =  \pm  \sqrt{1} }

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

<u>C</u><u>o</u><u>n</u><u>c</u><u>l</u><u>u</u><u>s</u><u>i</u><u>o</u><u>n</u>

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0
2 years ago
Read 2 more answers
What is 3/4-5/8?<br> ? Give your answer in its simplest form.
Setler79 [48]

Answer:

1 over 8

1

8

=0.125

Step-by-step explanation:

8 0
2 years ago
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