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Alex73 [517]
3 years ago
10

X – y = 23x + y = 10all of yalls answer r wrong the answer is x= 3 and y= 1 ​

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

Step-by-step explanation:

People always get it wrong just for points

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y= x + 3

Step-by-step explanation:

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12
Anna [14]

5 x 3²⁴  bacteria will there be after one day.

What is exponents?

Exponentiation could be a calculation, written as bⁿ, involving 2 numbers, the bottom b and also the exponent or power n, and pronounced as "b to the n".

Consider what is actually happening in the question.

You begin with 5 bacteria, and after 1 hour it has tripled so you now have

5x 3=15.

Next hour, it triples again so you now have 5 x 3 x 3=45

You can see the pattern shows that the number of bacteria is multiplying every hour by a factor of 3. An exponent denotes how many times we are multiplying a number by itself, for example: 3⁴  means we are multiplying the number 3 a total of 4 times (3 x 3 x 3 x 3).

Therefore the question is requiring us to triple the number of bacteria every hour for 24 hours, which means we are multiplying by 3 a total of 24 times. This gives us:

n x 324 where n is the number of bacteria you begin with.

Since you begin with 1 bacteria, the solution is 5 x 3²⁴.

Hence 5 x 3²⁴  bacteria will there be after one day.

To know more about exponents , visit:

brainly.com/question/13669161

#SPJ1

8 0
1 year ago
Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors
dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

a(t) = (5,5t, 8t)

v(t) can be obtained by integrating a(t)

v(t) = (5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0
3 years ago
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