Three consecutive numbers are x, x+1 and x+2.
Four times the first integer is 4x
The sum of the second and third is (x+1)+(x+2)=2x+3.
So, we have

Subtract 2x from both sides:

Divide both sides by 2:

So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.
In fact, you have

and

Answer:
The answer is C so X is=16
Step-by-step explanation:
X^a times X^b = X^a + b
so 4x times 6x = 24x^(1+1)
Answer: The answer is 2
Step-by-step explanation:
3j + 4 = 10 J = 2
3x2=6
6+4= 10
The answer is .1391
Hope this helps!
(If your confused, I just put this in a calculator)