Ask question

Ask question

All categories

2 years ago

13

What is the slope of H= -0.10t+2

1 answer:

Mkey [24]2 years ago

4 0

Answer: t=−10h+20

Step-by-step explanation:

You might be interested in

Alan estimated that he would score 140 points the next time he bowled. He actually scored 152 points. What was the percent error

slava [35]

Given:
estimate = 140
actual = 152

Percent of error = |(estimate - actual)/actual| * 100%

% of error = |140 - 152| / 152 * 100%
= |-12|/152 * 100%
= 0.0789 x 100%
% of error = 7.89% rounded to the nearest tenth 7.9%

3 0

2 years ago

Read 2 more answers

Megan creates a scale drawing of a car. The ratio of her scale drawing length to actual car

Alika [10]

Answer:

Givens

The length of the car in her drawing is 6 cm.
The scale is 3 cm : 2 m.
Ivan draws with a relation 2 cm : 1 m.

First, we need to find the actual length of the car using Megan's ratio.

If 2 centimeters is equivalent to 1 actual meter of the car, 6 centimeters of drawing would be equal to

$M=6cm \times \frac{2m}{3cm} =4m$

Therefore, the car is 4 meters long.

Now, using this information, we can find the length of the scale drawing of Ivan.

$I=4m \times \frac{2cm}{1m}=8cm$

Therefore, Ivan's drawing is 8 centimeters long.

6 0

2 years ago

Read 2 more answers

The price of gas last summer was $3.80 and this summer it is $1.90. What is the percent of decrease.

Marianna [84]

It was a 50% decrease.

7 0

2 years ago

Read 2 more answers

Arjun has to pack 15,276 pastries into boxes of 6 pastries each. He has to pack all the pastries.

Musya8 [376]

Answer:

No, Arjun would need 2546 boxes

Step-by-step explanation:

Since he needs to pack 15,276 pastries into boxes of 6, this equation can be used to determine the amount of boxes needed. Hope this helps!

6 0

2 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

1 year ago