Answer:
-20c^3
Step-by-step explanation:
((−5c)(d−4))((2cd2)2)
=
−20c3d4
/d4
=-20c^3
Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) The expected value of x is defined as

c) The variance of x is defined as

d) The standard deviation of x is defined as



Preliminary Problem
Givens
Miles = m = 392 miles
Gallons = G = 14 gallons
Miles per gallon = mpg
Formula
miles = miles per gallon * number of gallons.
Solve
392 = mpg * 14 Divide by 14
392 / 14 = mpg
28 = mpg which is really quite good. Our vehicle gets 44 mpg but it's a 4 cylinder. It's meant to get that kind of milage.
Part A
Let x = the number of gallons used
Let y = the number of miles driven
y = k*x
Part B
y = k* x
k =28 mpg
11700 = 28*x
11700 /28 = x
x = 417.86
If this is incorrect please put some more facts in. The question does not seem complete.
Answer:
Students:Adults = 118:94
Step-by-step explanation:
212-118=94