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Iteru [2.4K]
3 years ago
12

Unit 2 Functions Classwork - Homework Day 5 Piecewise Functions

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0
Yatrsiwnbcshsutacshbsvsy
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I WILL MARK BRAINLIEST
Ber [7]

Answer:

N is (8,5)

Step-by-step explanation:

Find the difference between M, and A, then add it to the M coordinates

The difference between M (x) and A (x) is 3, so you have to add 3 to M's x coordinate to get the N's x coordinate.

Do the same for the y coords and you will get (8,5)

5 0
2 years ago
Triangles and algebra
Scorpion4ik [409]
X-30+x-30+x=180

3x-60=180

3x=240
X=80
6 0
2 years ago
LCM of 4/6 and 4/8????
Svet_ta [14]

Answer:

24 is the LCM of 4,6,8. I think thats what your looking for.

Hope this helps!

Step-by-step explanation:

5 0
2 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
37. Two numbers are such that their
omeli [17]

Answer:

8 and 6

Step-by-step explanation:

Two numbers are such that their difference, their sum, and their product are to

each other as 1:7:24. Their product must equal what number?

:

Two numbers a & b

Let x = the multiplier

:

a - b = 1x

a + b = 7x

a * b = 24x

:

Add the 1st two equations

a - b = x

a + b = 7x

2a = 8x

a = 4x

or

x = .25a

:

a * b = 24x

Replace 24x; a = 4x therefore:

a * b = 6a

b = 6

;

Using the 1st equation

a - b = 1x

Replace b with 6 and x with .25a

a - 6 = .25a

a - .25a = 6

.75a = 6

a =

a = 8

:

Find the multiplier

a - b = x

8 - 6 = 2

:

Check this

a - b = 2 (1*2)

a + b = 14; (7*2)

a * b = 48: (24*2)

:

The numbers are 8 and 6; their products = 48

4 0
3 years ago
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