Unit 2 Functions Classwork - Homework Day 5 Piecewise Functions

Alik [6]

The correct answer is that Hector placed Puppy 3 at -3.4 instead of at -0.75.
So A would be your correct answer. -3/4 is equivalent to -0.75. Think of it like money. 4 quarters equals $1.00. 3 quarters is 75 cents, or .75 which is this. Don’t forget the signs though. God bless you.

4 0

3 years ago

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A projectile is fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. How long

____ [38]

Answer:

Step-by-step explanation:

We will work in the y-dimension only here. What we need to remember is that acceleration in this dimension is -9.8 m/s/s and that when the projectile reaches its max height, it is here that the final velocity = 0. Another thing we have to remember is that an object reaches its max height exactly halfway through its travels. Putting all of that together, we will solve for t using the following equation.

$v=v_0+at$

BUT we do not have the upwards velocity of the projectile, we only have the "blanket" velocity. Initial velocity is different in both the x and y dimension. We have formulas to find the initial velocity having been given the "blanket" (or generic) velocity and the angle of inclination. Since we are only working in the y dimension, the formula is

$v_{0y}=V_0sin\theta$ so solving for this initial velocity specific to the y dimension:

$v_{0y}=35sin(35)$ so

$v_{0y}=$ 2.0 × 10¹ m/s

NOW we can fill in our equation from above:

0 = 2.0 × 10¹ + (-9.8)t and

-2.0 × 10¹ = -9.8t so

t = 2.0 seconds

This is how long it takes for the projectile to reach its max height. It will then fall back down to the ground for a total time of 4.0 seconds.

8 0

3 years ago

Which of the following circles have their centers on the y-axis check all that apply

konstantin123 [22]

B and c because i get it because I have magic powersssss

3 0

3 years ago

Which of these choices are quadratic equations? Check all that apply.

balandron [24]

Answer:

A

Step-by-step explanation:

3 0

3 years ago

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I am soooo confuseddd what the heckkk Ok so Im doing something called 'Graphing Systems of Linear Equations' , well you might sa

horsena [70]

Okay, so the equation for the y-intercept is y=mx+b, this will be your base for graphing anything.

For y = x + 3 it's basically y = 1x + 3. Use b as the y-intercept, or 3, and plot it as (x,y), (0,3). Then use m as the slope, or 1. 1 means positive one so the point goes (0,3), (1, 4), (2, 5).

For y = -3x - 1 it's the same thing but different numbers. Use b, the y-intercept, and plot it. -1 is b, so plot (0,-1). Then use the slope to go up or down the direction you need to go, or m. m is -3, so for every +1 in x, the y will decrease by 3. (0,-1), (0,-4), (0,-7).

I hope this helped in some way or increased your understanding!

4 0

2 years ago