Is there a b ok but it’s A
Answer:
Z is 66. If you want an explanation, I could give it to you, FYI.
Answer:
So the right answer is none
Step-by-step explanation:
-6≤1+3x
3x≥-7
x≥-2,33
-2,33>-5>-6>-11
so none of those are bigger then -2,33 and x is bigger then -2,33
Happy New Year from MrBillDoesMath!
Answer:
Proof by ASA congruence postulate. See below
Discussion:
Fact 1 : angle A = angle T (given)
Fact 2: The angles on both sides of point X are equal as vertical angles
are equal.
From these facts it follows that angle M = angle H (as all plane triangles have 180 degrees). Also AM = TH (given) so
In the left triangle In the right triangle
(angle M, side AM, angle A) = (angle H, side TH, angle T)
Hence the triangles have two congruent angles, and congruent sides included between the angles, so they are congruent by ASA.
Thank you,
MrB
Answer:
C = 5.
Step-by-step explanation:
First, you need to remember that:
For the function:
h(x) = Sinh(k*x)
We have:
h'(x) = k*Cosh(k*x)
and for the Cosh function:
g(x) = Cosh(k*x)
g'(x) = k*Cosh(k*x).
Now let's go to our problem:
We have f(x) = A*cosh(C*x) + B*Sinh(C*x)
We want to find the value of C such that:
f''(x) = 25*f(x)
So let's derive f(x):
f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)
and again:
f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)
f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)
And we wanted to get:
f''(x) = 25*f(x) = C^2*f(x)
then:
25 = C^2
√25 = C
And because we know that C > 0, we take the positive solution of the square root, then:
C = 5
