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4 years ago

Can y’all help me with this please will give you the brainliest

Mathematics

1 answer:

polet [3.4K]4 years ago

6 0

Answer and Step-by-step explanation:

A pair of segments that are perpendicular to each other are the line segments:

KI (the letter i) and MJ.

This is because we see that at the intersection T, there a right angle symbol, which means that those 4 angles at the intersection are 90 degrees. When a line meets another line, and it is perpendicular to that line, they form 90 degrees.

So, those line segments are perpendicular.

#teamtrees #WAP (Water And Plant)

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Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

tankabanditka [31]

Answer:

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

Step-by-step explanation:

Given - y = 1/x+1

To find - Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

Proof -

We know that,

Slope of tangent line = f'(x) = $\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$

We have,

f(x) = y = $\frac{1}{x+1}$

So,

f(x+h) = $\frac{1}{x+h+1}$

Now,

Slope = f'(x)

And

$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \\= \lim_{h \to 0} \frac{\frac{1}{x+h+1} - \frac{1}{x+1} }{h}\\= \lim_{h \to 0} \frac{x+1 - (x+h+1) }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{x +1 - x-h-1 }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-h }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-1 }{(x+1)(x+h+1)}\\= \frac{-1 }{(x+1)(x+0+1)}\\= \frac{-1 }{(x+1)(x+1)}\\= \frac{-1 }{(x+1)^{2} }$

∴ we get

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

6 0

3 years ago

What's the answer? help asap plssssss Please show full explanation!

AURORKA [14]

Answer:

$\huge\boxed{Answer\hookleftarrow}$

Given,

$3x - 2y = 5$

$xy = - 2$

Now,

$(3x - 2y) {}^{2} = (5) {}^{2} \\$

Use the algebraic identity ⇻ (a - b)² = a² - 2ab + b²

$(3x - 2y) {}^{2} = (5) {}^{2} \\ 3x {}^{2} - 2 \times 3x \times 2y + 2y {}^{2} = 5 {}^{2} \\ 9 {x}^{2} - 12xy + 4y {}^{2} = 25 \\9x {}^{2} + 4y {}^{2} = 25 + 12xy \\ 9x {}^{2} + 4 {y}^{2} - 1 = 24 + 12xy$