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Nostrana [21]
3 years ago
12

What are the rules to remember while working with Proportional Relationships?

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

Some textbooks describe a proportional relationship by saying that " y varies proportionally with x " or that " y is directly proportional to x ." This means that as x increases, y increases and as x decreases, y decreases-and that the ratio between them always stays the same.

Step-by-step explanation:

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shusha [124]

Answer:

f'(x) =  {e}^{x}(  \sin x + \cos x )

Step-by-step explanation:

f(x) =  {e}^{x}  \sin  x \\  \\ f'(x) = \sin x \frac{d}{dx}  {e}^{x}  + {e}^{x}  \frac{d}{dx}  \sin x \\  \\ f'(x) =  \sin x \: {e}^{x}   +{e}^{x}  \cos x \\  \\ f'(x) =  {e}^{x}(  \sin x + \cos x )

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3 years ago
Identifying functions from relations
Mashutka [201]
I don’t know but I need the Points sorry for you
4 0
1 year ago
F(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2-4%7D" id="TexFormula1" title="\sqrt{x^2-4}" alt="\sqrt{x^2-4}" align="abs
hammer [34]

Solve for <em>x</em> when √(<em>x</em> ² - 4) = 1 :

√(<em>x</em> ² - 4) = 1

<em>x</em> ² - 4 = 1

<em>x</em> ² = 5

<em>x</em> = ±√5

We're looking at <em>x </em>≤ 0, so we take the negative square root, <em>x</em> = -√5.

This means <em>f</em> (-√5) = 1, or in terms of the inverse of <em>f</em>, we have <em>f</em> ⁻¹(1) = -√5.

Now apply the inverse function theorem:

If <em>f(a)</em> = <em>b</em>, then  (<em>f</em> ⁻¹)'(<em>b</em>) = 1 / <em>f '(a)</em>.

We have

<em>f(x)</em> = √(<em>x</em> ² - 4)   →   <em>f '(x)</em> = <em>x</em> / √(<em>x</em> ² - 4)

So if <em>a</em> = -√5 and <em>b</em> = 1, we get

(<em>f</em> ⁻¹)'(1) = 1 / <em>f '</em> (-√5)

(<em>f</em> ⁻¹)'(1) = √((-√5)² - 4) / (-√5) = -1/√5

The sign must be negative; see the attached plot, and take note of the negatively-sloped tangent line to the inverse of <em>f</em> at <em>x</em> = 1.

3 0
3 years ago
Enter an equation of the form y= mx for the line that passes through the
hammer [34]

Answer:

y = 13x

Step-by-step explanation:

gradient = 13

x = 0

y = 0

\frac{Δy}{Δx}

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cross multiply and you get

y = 13x

5 0
3 years ago
Which of the following pairs of numbers contains like fractions?
Harrizon [31]

Answer:

D

Step-by-step explanation:

if you multiply 5 by 2 you get 10

if you multiply 6 by 2 you get 12

5/2 (2) =10/12

Hope this helped

:)

4 0
3 years ago
Read 2 more answers
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