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2 years ago

11

Which two changes would make this reaction product-favored? 3H2 + N2 ⇄ 2NH3 + energy A. Decreasing the pressure B. Increasin

g the temperature C. Increasing the pressure D. Reducing the temperature

2 answers:

Dennis_Churaev [7]2 years ago

7 0

Answer:C and D

Explanation:Just did it

lapo4ka [179]2 years ago

7 0

Answer:

C+D

Explanation:

Ap3x

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Pls help will give brainlist

jekas [21]

Answer:

D. 5

Explanation:

The coefficient will almost always be the whole number in front of the variable.

example

5(x)= 7

The coefficient would be 5.

6 0

2 years ago

Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?

irina [24]

Formula: molality, m = n solute / kg solvent

n solute = # of moles of solute = mass(g) / molar mass

Molar mass of Mg Br2 = 184.11 g/mol

m = [46g / 184.11 g/mol] / 0.5 kg = 0.50 mol/kg

3 0

3 years ago

The OH- ion concentration is greater than the H3o+ ion concentration in a water solution of

cupoosta [38]

Answer:

B) CH₃OH

Explanation:

7 0

3 years ago

true or false electrical energy is the amount of energy that contains an object due to the kinetic energy?

yuradex [85]

The answer to this question would be true.

4 0

2 years ago

Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?

Irina18 [472]

Answer:

$p_2=1.17atm$

Explanation:

Hello!

In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

$\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\$

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

$p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm$

Best regards!

7 0

2 years ago