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raketka [301]
3 years ago
15

Consider a reactant with an order of 1: What effect does that reactant have on the rate equation when the concentration is doubl

ed 1) The reaction rate is double with respect to that reactant 2) The order doesnt effect the reaction so there will be no change 3) The reaction rate quadruples with respect to that reactant. 4) The reaction rate isn't changed by individual reactants so there will be no change.
Chemistry
1 answer:
____ [38]3 years ago
6 0

Answer:

1) The reaction rate is double with respect to that reactant

Explanation:

Hello,

By considering the rate law:

-r_A=kC_A

If we double the reactant A concentration, by definition, the rate will be doubled as well since the C_A power is one (order 1), this could be proved just by checking it out in the rate law.

Best regards.

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The answers please to this
Vlad1618 [11]
I know for number 4 the answer is c, sorry I can't help with the others.
5 0
3 years ago
A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
erica [24]

Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

V_2=\frac{V_1*n_2}{n_1}

Thereby, we plug in to obtain:

V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L

Best regards!

4 0
3 years ago
Questions in pic plz help .
Paladinen [302]

Answer:

c

Explanation:

6 0
3 years ago
What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?
Sever21 [200]

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

= 24 ounces = 709.68 mL

(1 ounces =  29.57 mL)

Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}

x = 295.7 mL

295.7 mL of 24% trichloroacetic acid (tca) is needed .

6 0
3 years ago
What is the ratio of effusion rates of krypton and neon at the same temperature and pressure?
egoroff_w [7]
The formula we use would be the graham's law. We do as follows:

<span>E_Kr / E_Ne = sqrt ( M_Ne / M_Kr) 
</span>
<span>= sqrt ( 20.1797 g/mol / 83.798 g/mol ) </span>
<span>= sqrt (0.24081) </span>
<span>= 0.4907
</span>
Hope this answers the question. Have a nice day.
7 0
3 years ago
Read 2 more answers
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