Your answer is 1-3-2-4 , grass sand water rock
<u>Answer:</u> The mass of iron in the ore is 10.9 g
<u>Explanation:</u>
We are given:
Mass of iron (III) oxide = 15.6 g
We know that:
Molar mass of Iron (III) oxide = 159.69 g/mol
Molar mass of iron atom = 55.85 g/mol
As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.
To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:
In 159.69 g of iron (III) oxide, mass of iron present is 
So, in 15.6 g of iron (III) oxide, mass of iron present will be = 
Hence, the mass of iron in the ore is 10.9 g
Explanation:
The species or elements which gain electrons and reduces itself are known as oxidizing agent or oxidant.
Ability of an element to act as an oxidizing agent depends on its electrode potential.
The electrode potential of
is 0.52 V.
The electrode potential of
is -0.41 V.
The electrode potential of
is -2.38 V.
Greater is the value of electrode potential, stronger will be the oxidizing agent.
Therefore, rank of these species by their ability to act as an oxidizing agent are as follows.
>
> 
this is due to the difference in electron density. Butylamine has more electron density than ammonia. Due to this reason is a Butylamine stronger base than ammonia. BUtylamine has positive induction effect of -CH3 group electron density on N atom which increases
1 roll of nickels has 40 nickles.
40 * 3 = 120
120 nickels in 3 rolls of nickels.