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3 years ago

Solve each system of equations. 2x- 4y = 20 x=4

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

7 0

Answer:

(x,y)=(4,-3)

Step-by-step explanation:

2x- 4y = 20

x=4

Substitute the value of x

2*4-4y=20

Solve equation

y=-3

A possible solution is

(x,y)=(4,-3)

Check the solution

2*4-4*(-3)=20

4=4

Simplify

20=20

4=4

The ordered pair is the solution

Mrac [35]3 years ago

4 0

Answer:

Y=20

Step-by-step explanation:

If x=4 then you could rewrite the equation as:

2(4)-4y=20

8-4y=20

With this equation (8-4y=20) you would have to divide 4y by 4 and 8 by 4 which allows you to rewrite the equation as:

2-y=20

and here we would do inverse operations which, since it's 2-y we would change that to +2 which cancels out the 2-y and because we did it to one side we do it to the other- changing the equation to:

y=22

Sorry this was such a sloppy explanation, it's very difficult to type a response instead of having a visual representation! Apologies, hope this was somewhat helpful. xx

Y=22

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ohn is interested in purchasing a multi-office building containing five offices. The current owner provides the following probab

Galina-37 [17]

Answer:

$28,875

Step-by-step explanation:

The given table is:

$\left|\begin{array}{c|cccccc}$Number of Lease Offices&0&1&2&3&4&5\\$Probability&5/32&3/16&3/32&1/4&9/32&1/32\end{array}\right|$

The expected probability is derived using the formula: $\sum_{i=0}^{5}x_iP(x_i)$

Therefore, for the given distribution,

Expected Probability

$=(0*\frac{5}{32})+ (1*\frac{3}{16})+ (2*\frac{3}{32})+ (3*\frac{1}{4})+ (4*\frac{9}{32})+ (5*\frac{1}{32})\\=2.40625$

If each yearly lease is $12,000

The Expected Yearly Lease for the Whole Building=2.40625 X 12000

=$28,875

4 0

3 years ago

The difference between two positive integers is 54. One integer is three times as great as the other. Find the integer

sveta [45]

The answer is 27
27+54=81 and 27x3= 81
:)

7 0

4 years ago

PLEASE HELP!!

Ratling [72]

All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).

These probabilities are computed as 1 over all the possible outcomes.

(a) If you want a heart card and a five, you want the 5 of hearts. So, only one card would satisfy your request, and thus you have probability 1/52 of dealing the 5 of hearts.

$\dfrac{1}{52}\approx 0.019 = 1.9\%$