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nikitadnepr [17]
3 years ago
11

Plz help!? Identify the part of the graph that shows:

Biology
1 answer:
san4es73 [151]3 years ago
6 0

Answer:

Answer in order: C, A, B

Explanation:

But I'm not the brightest at this subject, but what I did is just observed what I thought the answers were thoroughly by using the keywords and letters and then matching them together to make sense. I remember doing this, but let me know if it's wrong!

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PLEASE solve number 1 and 2 because i don’t get it , don’t mind my answers
Readme [11.4K]

Answer:

1) RNA strand =  <em>UCA  GCA  AAU</em>

<em>2) </em>Amino acids:   Asparagine       Arginine             Stop

                            (ASN)               (ARG)              (STOP)

Explanation:

Some theory that you need to know to answer the question:

Each tRNA has two important sites. One of them that couples with the codon of the mRNA molecule, named <em>anticodon</em><em>.</em> The other site couples with an amino acid through the action of the aminoacyl-tRNA synthase enzyme. The whole complex, amino acid + enzyme + tRNA is named aminoacyl-tRNA. Considering that there are twenty amino acids available, there are also twenty complexes of aminoacyl-tRNA, one for each amino acid.  

tRNA allows amino acids to align according to the nucleotidic sequence in the mRNA molecule.  

Once the new amino acid joins the growing peptidic chain, the binding between the amino acid and the tRNA molecule breaks. The tRNA is now free to join another amino acid and repeat the cycle.  

Now, to fill in the boxes, you need to pay attention to two things:

• <u>Anticodon</u>: In this box, you need to place the sequence of bases that pairs with the mRNA codon.  

• <u>Amino Acid</u>: In this box, you need to place the amino acid that is codified by the<u> mRNA </u>codon.  

For instance, let us say that the codon of mRNA is CUC. The anticodon for this sequence is GAG (because guanine joins cytosine and adenine joins uracyl).  

The amino acid places on the 3´extreme of the tRNA molecule will be the one that is codified by the codon, NOT the anticodon. So, as the codon is CUC, the amino acid will be Leucine, Leu. Do not use the anticodon GAG to fill these boxes. Remember that tRNA is translating information carried by the mRNA, so we need to use this information to grow the protein.

<em />

1)

Strand of DNI  →  AGT  CGT  TTA

  • Each of these letters are bases → Adenine, A - Guanine, G - Thymine, T - Cytocine, C
  • Each of these three-lettered groups are codons.

So, we need to pair these bases, knowing that:

Adenine (A) and guanine (G) derive from purines, while Thymine (T) Uracile (U), and Cytosine (C) derive from Pyrimidines.  

In the DNA molecule, Adenine (Purine) always pairs with Timine (Pyrimidine), while Guanine (Purin) forms pairs with Cytosine.

In the RNA molecule,<em> Adenine is paired with Uracil, U. </em>So, whenever there is an Adenine in the DNI strand, it pairs with Uracil of RNA strand. If there is a Thymine in the DNI strand, it pairs Adenine of the RNA strand. And, as always, Guanine pairs with Cytosine.

  • A ⇒ U
  • T ⇒ A
  • G ⇔ C

Knowing how to pair bases, we can fill the RNA molecule boxes.

  • Strand of DNI  →  AGT                   CGT              TTA
  • <em>Strand of RNA →  UCA                  GCA              AAU</em>

<em>                                      A ⇒ U              C ⇒ G            T ⇒ A</em>

<em>                                     G ⇒ C               G ⇒ C            T ⇒ A</em>

<em>                                     T ⇒ A                T ⇒ A            A ⇒ U</em>

2)

Now we need to translate these new codons of mRNA to amino acids.

<em>To fill the boxes you should have a genetic code chart to see the codons that codify for each amino acid. </em>

Codon:                 AAU                 CGA                UAG

Amino acids:   Asparagine       Arginine             Stop

                            (ASN)               (ARG)              (STOP)

<em>The new protein is synthesized from the amino terminus to the carboxy terminus of the mRNA molecule. The added amino acids to the chain are coded by a codon formed by three bases in the mRNA. mARNs also have a start and end codon that are the signals of the synthesis initiation and finish. When the ribosome reaches a stop codon, protein synthesis is over.  </em>

<em />

8 0
3 years ago
Osmosis is like diffusion but refers to the movement of
n200080 [17]
Osmosis refers to the movement of water!!
5 0
2 years ago
In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t
Sergio [31]

Answer:

The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² +  2pq+ q²  = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = \sqrt{0.35} = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

8 0
3 years ago
Based on the graph above, what conclusion can be drawn about the relationship between temperature and absolute magnitude (bright
Sidana [21]

Answer:

i think it D

Explanation:

Hope it helps

6 0
3 years ago
What is the difference between a habitat and an ecosystem?
Mariulka [41]
Hope this helps !! :) good luck
3 0
3 years ago
Read 2 more answers
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