Graph the pre-image A(-1,0) B(2,5) C(-1,5)
2 answers:
You might be interested in
(6y - 11)(6y + 11) = ay² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
Answer:
A 190-pound person would burn 285 calories at the same rate.
Step-by-step explanation:
<em>Calories burn depends on the weight</em>
<em>Weight of first person = 160</em>
Calories burn for 160 pounds in 30 mins = 237
Calories burn rate for 1 pound in 30 mins = = 1.5
<em>Calories burn for 190 Pound person would be:</em>
Weight of second person = 190
Calories burn for 190 pounds in 30 min:
As the burn rate of calories is same for the two persons:
= rate × weight
= 1.5 * 190
= 285 calories