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tensa zangetsu [6.8K]
2 years ago
14

Select ONE of these problems to solve. STAR the problem and then write the expression first. After you write the expression, sol

ve it.​

Mathematics
2 answers:
Gwar [14]2 years ago
6 0
An expression that represents the total calories for ‘n’ Big Macs is:
550n
Use the expression to solve the total calories in 17 Big Macs:
550(17) = 9350

THEREFORE, there are 9350 calories in 17 Big Macs.
saw5 [17]2 years ago
5 0
550n is the expression which shows the total calories for ‘n’ Big Macs.


The answer is 9350


Solution:

If there are 550 calories in a McDonald’s Big Mac, this means that there are 9350 calories in 17 Big Macs.

550 x 17 = number of calories in 17 Big Macs/ 9350 calories

Hopes this answers your question :)
You might be interested in
When solving negative one over five (x − 25) = 7, what is the correct sequence of operations? (5 points) a Multiply each side by
german

Answer:

Hello!!

When solving -\frac{1}{5} (x-25)=7, the correct sequence of operations would be...

Multiply each side by −5, add 25 to each side

Step-by-step explanation:

When completing the order of operations use PEMDAS Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

Hope this helps!!

7 0
2 years ago
To make a disinfecting solution, Alana mixes 2 cups of bleach with 5 cups of
lubasha [3.4K]

Answer:

Step-by-step explanation:

Ok

7 0
3 years ago
a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams. How much of the substance re
s344n2d4d5 [400]

Answer:

1.25 g

Step-by-step explanation:

you start with 20g at 0 seconds.

divide by half after 2 seconds and you have 10g.

at 4 seconds you have 5g.

at 6 seconds you have 2.5g.

at 8 seconds you have 1.25g.

5 0
2 years ago
Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and
ollegr [7]

Firstly, we'll fix the postions where the n women will be. We have n! forms to do that. So, we'll obtain a row like:

\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)

Since there is no women sitting together, we must write that x_2,x_3,...,x_{n-1},x_n\ge1. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}

The equation (i) can be rewritten as:

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\&#10;x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: \dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: m!

Multiplying all results:

n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\&#10;\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}

4 0
3 years ago
You work from 3:30 P.M. to 9:00 P.M. each day, Monday through Friday. You take an unpaid break from 6:00 to 6:30. How many hours
Sav [38]

Answer:362 hours

Step-by-step explanation:

4 0
2 years ago
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