U can pick either point to finish
y - 1 = 2(x-1)
y= 2x-2 +1
y = 2x-1
or
y-5 = 2(x-3)
y = 2x-6+5
y = 2x-1
Answer: The answer is -1/8
Step-by-step explanation:
3/4*2/3+3/4*-5/6
3 is cancelled out with 3, 4 with 2, 3 with 6
1/2-5/8
take the L.C.M
4(1)-1(5)/8
4-5/8
=-1/8
ANSWER
a) Orthogonal
b) Not orthogonal.
EXPLANATION
The given vectors are:
a)

and

If the dot product of two vectors is zero, then the two vectors are orthogonal.



These two vectors are orthogonal.
b)
The second pair of vectors are:

and




This pair is not orthogonal.
Answer:
Multiply each equation by the coefficient of y in the other one.
Step-by-step explanation:
(1) 6x + 5y = 2
(2) 4x + 2y = 8
Multiply each equation by the coefficient of y in the other one.
Multiply (1) by 2 and (2) by 5.
(3) 12x + 10y = 4
(4) 20 x + 10y = 40 Subtract (3) from (2)
8x = 36 Solve for x
x = 9/2