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abruzzese [7]
3 years ago
12

Can you do 2 problems? and then someone else do the other 2 ty!

Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

ill do perimeter

1. 46.2

2.69.9

3.57.4

4. 50.7

Step-by-step explanation:

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The data set represents the total number of tuba players in each of 11 different school bands. 0, 1, 3, 3, 4, 4, 4, 5, 6, 6, 8 W
DaniilM [7]
Data set: <span>0, 1, 3, 3, 4, 4, 4, 5, 6, 6, 8

minimum : 0
1st quartile: 2
median: 4
3rd quartile: 6
maximum: 8

mean: 4
mean average deviation: 1.64
interquartile range: 4
range: 8</span>
4 0
4 years ago
Read 2 more answers
30<br> 45<br> 60<br> Which is it? <br> Help please
blagie [28]

Answer:

D = 90°

Step-by-step explanation:

the square on the angle means its a right angle and right angle is always 90°

3 0
3 years ago
Susie plans to run 2 miles per day the first week and then increase the daily distance by a half a mile each of the following we
AlekseyPX

Due to length restrictions, we kindly invite to see the explanation below to know the answer with respect to each component of the question concerning linear equations.

<h3>How to determine a linear equation describing the daily distance of a runner</h3>

In this question we need to derive an expression of the <em>daily</em> distance as a function of time. Now we proceed to complete the components:

  1. <em>Linear</em> equations have an <em>independent</em> variable (t - time) and a dependent variable (x - daily distance).
  2. We notice that the daily distance increases linearly in time, then then we have the following pattern:

    t          1            2            3             4            5              6
    x          2          2.5          3           3.5           4             4.5
  3. The equation that represents the n-th term of the sequence is x(n) = 2 + 0.5 · (n - 1).
  4. The week when Susie will run 10 miles per day is:

    10 = 2 + 0.5 · (n - 1)
    8 = 0.5 · (n - 1)
    n - 1 = 16
    n = 17

    Susie will run 10 miles per day in the 17th week.
  5. It is not reasonable to think that pattern will continue indefinitely as it is witnessed in the difficulties experimented by <em>fastest</em> runners in the world to increase their <em>peak</em> speeds.
  6. A marathon has a distance of 26 miles, then we must solve the following equation:

    26 = 2 + 0.5 · (n - 1)
    24 = 0.5 · (n - 1)
    48 = n - 1
    n = 49

    Susie should start her training 49 weeks before the marathon.

To learn more on linear equation: brainly.com/question/11897796

#SPJ1

7 0
2 years ago
2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7 not pemdas
antiseptic1488 [7]

<em></em>

<em>60</em>

<em>See steps</em>

<em>Step by Step Solution:</em>

<em>More Icon</em>

<em>Reformatting the input :</em>

<em>Changes made to your input should not affect the solution:</em>

<em />

<em>(1): "2.7" was replaced by "(27/10)". 8 more similar replacement(s)</em>

<em />

<em>STEP</em>

<em>1</em>

<em>:</em>

<em>            27</em>

<em> Simplify   ——</em>

<em>            10</em>

<em>Equation at the end of step</em>

<em>1</em>

<em>:</em>

<em>     27 62   93 12    62 93    12 27</em>

<em>  (((——•——)-(——•——))+(——•——))-(——•——)</em>

<em>     10 10   10 10    10 10    10 10</em>

<em>STEP</em>

<em>2</em>

<em>:</em>

<em>            6</em>

<em> Simplify   —</em>

<em>            5</em>

<em>Equation at the end of step</em>

<em>2</em>

<em>:</em>

<em>     27 62   93 12    62 93    6 27</em>

<em>  (((——•——)-(——•——))+(——•——))-(—•——)</em>

<em>     10 10   10 10    10 10    5 10</em>

<em>STEP</em>

<em>3</em>

<em>:</em>

<em>            93</em>

<em> Simplify   ——</em>

<em>            10</em>

<em>Equation at the end of step</em>

<em>3</em>

<em>:</em>

<em>     27 62   93 12    62 93   81</em>

<em>  (((——•——)-(——•——))+(——•——))-——</em>

<em>     10 10   10 10    10 10   25</em>

<em>STEP</em>

<em>4</em>

<em>:</em>

<em>            31</em>

<em> Simplify   ——</em>

<em>            5 </em>

<em>Equation at the end of step</em>

<em>4</em>

<em>:</em>

<em>     27 62   93 12    31 93   81</em>

<em>  (((——•——)-(——•——))+(——•——))-——</em>

<em>     10 10   10 10    5  10   25</em>

<em>STEP</em>

<em>5</em>

<em>:</em>

<em>            6</em>

<em> Simplify   —</em>

<em>            5</em>

<em>Equation at the end of step</em>

<em>5</em>

<em>:</em>

<em>     27 62   93 6   2883  81</em>

<em>  (((——•——)-(——•—))+————)-——</em>

<em>     10 10   10 5    50   25</em>

<em>STEP</em>

<em>6</em>

<em>:</em>

<em>            93</em>

<em> Simplify   ——</em>

<em>            10</em>

<em>Equation at the end of step</em>

<em>6</em>

<em>:</em>

<em>     27 62   93 6   2883  81</em>

<em>  (((——•——)-(——•—))+————)-——</em>

<em>     10 10   10 5    50   25</em>

<em>STEP</em>

<em>7</em>

<em>:</em>

<em>            31</em>

<em> Simplify   ——</em>

<em>            5 </em>

<em>Equation at the end of step</em>

<em>7</em>

<em>:</em>

<em>     27   31     279     2883     81</em>

<em>  (((—— • ——) -  ———) +  ————) -  ——</em>

<em>     10   5      25       50      25</em>

<em>STEP</em>

<em>8</em>

<em>:</em>

<em>            27</em>

<em> Simplify   ——</em>

<em>            10</em>

<em>Equation at the end of step</em>

<em>8</em>

<em>:</em>

<em>     27   31     279     2883     81</em>

<em>  (((—— • ——) -  ———) +  ————) -  ——</em>

<em>     10   5      25       50      25</em>

<em>STEP</em>

<em>9</em>

<em>:</em>

<em>Calculating the Least Common Multiple</em>

<em> 9.1    Find the Least Common Multiple</em>

<em />

<em>      The left denominator is :       50 </em>

<em />

<em>      The right denominator is :       25 </em>

<em />

<em>        Number of times each prime factor</em>

<em>        appears in the factorization of:</em>

<em> Prime </em>

<em> Factor   Left </em>

<em> Denominator   Right </em>

<em> Denominator   L.C.M = Max </em>

<em> {Left,Right} </em>

<em>2 1 0 1</em>

<em>5 2 2 2</em>

<em> Product of all </em>

<em> Prime Factors  50 25 50</em>

<em />

<em>      Least Common Multiple:</em>

<em>      50 </em>

<em />

<em>Calculating Multipliers :</em>

<em> 9.2    Calculate multipliers for the two fractions</em>

<em />

<em />

<em>    Denote the Least Common Multiple by  L.C.M </em>

<em>    Denote the Left Multiplier by  Left_M </em>

<em>    Denote the Right Multiplier by  Right_M </em>

<em>    Denote the Left Deniminator by  L_Deno </em>

<em>    Denote the Right Multiplier by  R_Deno </em>

<em />

<em>   Left_M = L.C.M / L_Deno = 1</em>

<em />

<em>   Right_M = L.C.M / R_Deno = 2</em>

<em />

<em />

<em>Making Equivalent Fractions :</em>

<em> 9.3      Rewrite the two fractions into equivalent fractions</em>

<em />

<em>Two fractions are called equivalent if they have the same numeric value.</em>

<em />

<em>For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.</em>

<em />

<em>To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.</em>

<em />

<em>   L. Mult. • L. Num.      837</em>

<em>   ——————————————————  =   ———</em>

<em>         L.C.M             50 </em>

<em />

<em>   R. Mult. • R. Num.      279 • 2</em>

<em>   ——————————————————  =   ———————</em>

<em>         L.C.M               50   </em>

<em>Adding fractions that have a common denominator :</em>

<em> 9.4       Adding up the two equivalent fractions</em>

<em>Add the two equivalent fractions which now have a common denominator</em>

<em />

<em>Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:</em>

<em />

<em> 837 - (279 • 2)     279</em>

<em> ———————————————  =  ———</em>

<em>       50            50 </em>

<em>Equation at the end of step</em>

<em>9</em>

<em>:</em>

<em>   279    2883     81</em>

<em>  (——— +  ————) -  ——</em>

<em>   50      50      25</em>

<em>STEP</em>

<em>10</em>

<em>:</em>

<em>Adding fractions which have a common denominator</em>

<em> 10.1       Adding fractions which have a common denominator</em>

<em>Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:</em>

<em />

<em> 279 + 2883     1581</em>

<em> ——————————  =  ————</em>

<em>     50          25 </em>

<em>Equation at the end of step</em>

<em>10</em>

<em>:</em>

<em>  1581    81</em>

<em>  ———— -  ——</em>

<em> </em>  25     25

STEP

11

:

Adding fractions which have a common denominator

11.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1581 - (81)     60

———————————  =  ——

    25          1

Final result :

 60

7 0
3 years ago
Given h(x) =1/2 x + 4 find h(-4) + 2.
Lynna [10]

Hi there! :)

\large\boxed{h(-4) + 2 = 4}

h(x) = 1/2x + 4

Substitute in -4 for "x" to solve for h(-4):

h(-4) = 1/2(-4) + 4

h(-4) = -2 + 4

h(-4) = 2

Since we are solving for h(-4) + 2, add:

2 + 2 = 4.

8 0
3 years ago
Read 2 more answers
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