What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.

so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2
Answer:
45.
Step-by-step explanation:
To solve this equation, we must use PEMDAS...
The operations listed first must be solved first before we can continue.
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Using this, we find that we must complete the multiplication and division before we add or subtract.
20 / 2 - 10 + 3 * 15
= (20 / 2) - 10 + (3 * 15)
= 10 - 10 + 45
= 0 + 45
= 45
Hope this helps!
Answer:
(-4,1)
Step-by-step explanation:
Let us check the choices.
y > |x| - 5
- 1 > |4| - 5 = -1 NO (4,-1);
-4 > |-1| - 5 = -4 NO not(-1,-4)
1 > |-4| - 5 = -1 TRUE, yes (-4,1)
Answer:
there must be coordinates
Step-by-step explanation:
Answer:
4x^2-14x+6
Step-by-step explanation:
(4x-2)(x-3)
*use box method