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Gala2k [10]
3 years ago
14

A square of side x is cut out of a larger square of side y. What is the area of the remaining

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

The area of the remaining figure is y^2-x^2

Step-by-step explanation:

<u>Area of the Square Shape</u>

Given a square of side length x, the area is calculated by the formula:

A_x=x^2

It's given a square of side x is cut out of a larger square of side y. Please refer to the image below.

The area of the square of side length y is:

A_y=y^2

The shaded area of the remaining figure is the difference between both areas:

A=A_y-A_x

A=y^2-x^2

The area of the remaining figure is \mathbf{y^2-x^2}

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3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?
Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

If \bigtriangleup = 0, the equation has only one solution.

In this problem, we have that:

3x^{2} + kx + 3 = 0

So

a = 3, b = k, c = 3

\bigtriangleup = b^{2} - 4ac

\bigtriangleup = k^{2} - 4*3*3

\bigtriangleup = k^{2} - 36

We will only have one solution if \bigtriangleup = 0. So

\bigtriangleup = 0

k^{2} - 36 = 0

k^{2} = 36

k = \pm \sqrt{36}

k = \pm 6

For k = 6 or k = -6, the equation will have exactly one solution.

3 0
2 years ago
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15.8 + 21.8 = 37.6

37.6/2 = 18.8

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