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3 years ago

13,14,15,16 please help me

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer:

#14 (9+6)=(6+_)?

C.9 , becuase 9 plus 6 is 15, ANSWER C

answer A would be wrong becuase 15+6=21

answer B would be wrong becuase 8+6=14

answer D would be wrong because 7+6=13

Step-by-step explanation:

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perform the steps for dividing the two polynomials using synthetic division. state the quotient, q(x), and the remainder, r(x).

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This particular equation cannot be solved using synthetic division as you can only use synthetic division when divided by a linear factor.

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Megan's family had cakes on two days. The first day, they had 2 3/4 cakes left. The second day, they had 1 1/4 cakes left. How m

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Which are are solutions for x^2 + 5x – 1 > 6

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2 years ago

A trapezoidal prism undergoes a dilation. The surface area of the pre-image is 35 m². The surface area of the image is 315 m². T

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The original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

<h3>How does dilation affect length, area, and volume of an object?</h3>

Suppose a figure (pre image) is dilated (dilated image) by scale factor of k.

So, if a side of the figure is of length L units, and that of its similar figure is of M units, then:

L = k × M

where 'k' will be called as scale factor.

The linear things grow linearly like length, height etc.

The quantities which are squares or multiple of linear things twice grow by square of scale factor. Thus, we need to multiply or divide by k² to get each other corresponding quantity from their similar figures' quantities.

So area of first figure = k² × area of second figure

Similarly,

Volume of first figure = k³ × volume of second figure.

It is because we will need to multiply 3 linear quantities to get volume, which results in k getting multiplied 3 times, thus, cubed.

For this case, we're given that;

Surface area of pre-image = 35 m²
Surface area of dilated image = 315 m²
Height of pre-image = 5.8 m
Height of dilated image.

Let the scale fator of dilation be k.

Then:

So area of pre-image = k² × area of dilated image

Thus, we get:

$35 = k^2 \times 315\\\\k = \sqrt{\dfrac{35}{315}} = 1/3$

(took positive root as scaling is done by non-negative factors as only magnitude matters mostly)

Thus, we get:

Height of pre-image = (1/3) × Height of dilated image (say h)

$5.8 = (1/3) \times h\\h = 3 \times 5.8 = 17.4 \rm \: m$

Thus, the original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

Learn more about dilation here:

brainly.com/question/3266920

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