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jenyasd209 [6]
3 years ago
7

Segment XY is transformed using rigid transformation to get segment X′Y′ as shown in the graph.

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0
I’m unsure but I think it’s letter c
ozzi3 years ago
3 0
I think C sorry if I’m wrong!!
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What percent of 240$ is 12$​
ira [324]

Answer:

I think its 5%

12/240=0.05

0.05=5%

Sorry if its wrong I haven't studied about percentages yet in school

3 0
3 years ago
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Add the following polynomails -3x^2-2xy+y^2,-4x^2-xy+6y^2, x^2+6xy-y^2
Tomtit [17]

Answer:

When we add the given polynomials the result is

(-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=3(2(y^2-x^2)+xy)

Step-by-step explanation:

Given polynomials are

-3x^2-2xy+y^2 ,-4x^2-xy+6y^2 , x^2+6xy-y^2

Now addding the polynomials we get

(-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=-3x^2-2xy+y^2+-4x^2-xy+6y^2+x^2+6xy-y^2

=-6x^2+3xy+6y^2  (adding the like terms on RHS)

=3(-2x^2+xy+2y^2)  (taking 3 outside on RHS)

=3(2(-x^2+y^2)+xy)

Rewritting the above equation we get,

=3(2(y^2-x^2)+xy)

Therefore (-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=3(2(y^2-x^2)+xy)

When we add the given polynomials the result is

(-3x^2-2xy+y^2)+(-4x^2-xy+6y^2)+(x^2+6xy-y^2)=3(2(y^2-x^2)+xy)

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3 years ago
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Answer:

The answer is x=-10,10

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The maroon team and the orange team played a game of football. The maroon team scored 40 points and the orange team scored 12 po
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40:12 or 10:3......these are equivalent
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Algebra one math please help
Alchen [17]
30 is the answer because 30*25=750
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4 years ago
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