Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4
Hence P(Y=1|X=3)=0.125
For this equation, we can let c = the value of one coupon
<span>4c = 108 - 76 </span>
<span>4c = 32 </span>
<span>c= $8
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Answer:
A 4/605
Step-by-step explanation:
mathematics = 11 letters
P(m) = number of m's/total = 2/11
we replace it so we have mathematics = 11 letters
P(s) = number of s's/total = 1/11
not replacing it
we replace it so we have mathematic = 10 letters
P(vowel) = number of vowel/total = 4/10 = 2/5
P(m, replace,s, no replace, vowel) = 2/11* 1/11 * 2/5 = 4/605
Father and daguther together
father=180
father and daughter is 7 times daught
father+x=7x
180+x=7x
D is answer
and daughter=30lb
