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Maurinko [17]
2 years ago
10

How many ways can a person toss a coin 13 times so that the number of heads is between 7 and 10 inclusive?

Mathematics
1 answer:
maks197457 [2]2 years ago
3 0

Answer:

4004

Step-by-step explanation:

The number of combinations of choosing r objects from a group of n is nCr.

So the number of ways to get 7, 8, 9, or 10 heads from 13 coin tosses is:

₁₃C₇ + ₁₃C₈ + ₁₃C₉ + ₁₃C₁₀

= 1716 + 1287 + 715 + 286

= 4004

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Your answer is xy-1<span><span>
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</span></span></span>Hope this helps!
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3 years ago
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