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Maurinko [17]
3 years ago
10

How many ways can a person toss a coin 13 times so that the number of heads is between 7 and 10 inclusive?

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

4004

Step-by-step explanation:

The number of combinations of choosing r objects from a group of n is nCr.

So the number of ways to get 7, 8, 9, or 10 heads from 13 coin tosses is:

₁₃C₇ + ₁₃C₈ + ₁₃C₉ + ₁₃C₁₀

= 1716 + 1287 + 715 + 286

= 4004

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Answer:

1. x+4x

2. 5x

3. 6\frac{7}{x}

4. 4x-2x+15

5. (6+x)^2

Step-by-step explanation:

To write expressions remember these key words:

  • a number is a variable like x
  • sum is +
  • difference and subtracted is -
  • quotient is ÷
  • product is ×
  • reciprocal means flip like \frac{1}{9}---> \frac{9}{1}
  • square is an exponent of 2 like x^2

1. x+4x

2. 5x

3. 6\frac{7}{x}

Remember a quotient would be \frac{x}{7}but the reciprocal is \frac{7}{x}.

4. 4x-2x+15

5. (6+x)^2

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3 years ago
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Answer:

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Step-by-step explanation:

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vazorg [7]

Answer:

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Step-by-step explanation:

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Another way of looking at it is for the totals.  there are 550 total, so 2/5 of that is green.  2/5 of 550 is 220, while 3/5 is 330  so that means of the 550, the ratio is 220:330.  Kinda like simplifying fractions where 220/550 is the same thing as 2/5

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