To answer the problem above, we must first define the word break even. Break even means there is no gain or loss, the difference between the capital amount and the sale amount is zero. In equation, let x be the number of pies. 5x + 30 = 12x, $5 times the number of pies plus $30 is equal to $12 times the number of pies sold. The answer is letter C.
The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.
The given polynomial is

What is the form of perfect square polynomial?

we solve this method by using perfect square method
add and subtract 1/9

factor 36

Now complete the square
Therefore this is not perfect square trinomial.
Similarly for

Complete square is,

This polynomial is also not perfect square trinomial.

complete square is,

This polynomial is not perfect square trinomial.

complete square is,

This polynomial is perfect square trinomial.
Therefore,
The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.
To learn more about perfect square trinomial visit:
brainly.com/question/1538726
Answer:
The graph is attached below.
Step-by-step explanation:
<em>As you have not added the graph, so I will be solving the function for a graph.</em>
Given the function









As we know that the domain of a function is the set of input or argument values for which the function is real and defined.





The graph is attached below.
Answer:
15.71
Step-by-step explanation:
10*3.142=31.42
31.42/2=
15.71