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3 years ago

8

Jese hangs 3 t shirt on a line. any t shirt next to each other share a peg. he uses 4 pegs. how may peg jess use to hang 6 t shi

rts next to each other?

1 answer:

Ivenika [448]3 years ago

7 0

He will use 7 pegs in total to hang 6 t shirts in line

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For the first triangle add 45 and 95 and subtract it from 180

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3 years ago

Help sense No one understands.

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3 years ago

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The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

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3 years ago

I have the question in a screengrab. Thank you, whoever helps me.

nata0808 [166]

To simplify

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we need to use the fact that

$\sqrt[4]{x^4}=|x|$

Why the absolute value? It's because $(-x)^4=(-1)^4x^4=x^4$ .

We start by rewriting as

$\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}$

$\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}$

Since $x\neq0$ , we have $\dfrac xx=1$ , and the above reduces to

$\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}$

Then we pull out any 4th powers under the radical, and simplify everything we can:

$\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}$

$\dfrac1{|2y|}\sqrt[4]{3x^2}$

where $y>0$ allows us to write $\dfrac yy=1$ , and this also means that $|y|=y$ . So we end up with

$\dfrac{\sqrt[4]{3x^2}}{2y}$

making the last option the correct answer.

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3 years ago

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

Leto [7]

<h2>Number of bacteria after 6 days is 2313</h2>

Step-by-step explanation:

Population after n days is given by

$P_n=P_0(1+r)^n$

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Increase rate, r = 15 % = 0.15

Number of days, n = 6

Substituting

$P_n=P_0(1+r)^n\\\\P_6=1000(1+0.15)^6\\\\P_6=1000(1.15)^6\\\\P_6=1000\times 2.313\\\\P_6=2313$

Number of bacteria after 6 days = 2313

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3 years ago

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