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Elena-2011 [213]
3 years ago
14

A teacher will never give a student any additional information about a test in a one-on-one meeting because it would not be fair

to the other students. Please select the best answer from the choices provided T F
Physics
2 answers:
laila [671]3 years ago
5 0

Answer:

False

Explanation:

Nataly [62]3 years ago
5 0

Answer:

true

Explanation:

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While standing in the middle of a mountain range, a camper is curious to see what would happen if he yelled loudly into the dist
Vera_Pavlovna [14]

Answer:

Reverberation

Explanation:

6 0
3 years ago
A 7000-kg plane is launched from an aircraft carrier in 2.0 seconds
ExtremeBDS [4]

The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively

To calculate the acceleration of the plane, we use the formula below.

<h3>Formula:</h3>
  • a = F/m..................... Equation 1

Where:

  • a = Acceleration of the plane
  • F = Force applied to the plane
  • m = mass of the plane.

From the question,

Given:

  • F = 550000 N
  • m = 7000 kg

Substitute these values into equation 1

  • a = 550000/7000
  • a = 78.57 m/s²

To calculate the velocity, we use the formula below.

  • v = u+at............. Equation 2

Where:

  • v = Final velocity
  • u = initial velocity
  • a = acceleration
  • t = time.

From the question,

Given:

  • u = 0 m/s
  • a = 78.57 m/s
  • t = 2.0 seconds

Substitute these values into equation 2

  • v = 0+2(78.57)
  • v = 157.14 m/s

Hence, The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively.
Learn more about acceleration here: brainly.com/question/460763

5 0
2 years ago
YALL HELP ME QUICK IN 10 MINS<br> WITH WORKING OUT
svetlana [45]

Answer:

bro I'm sorry I'm only in 7th grade

8 0
3 years ago
Read 2 more answers
(1) Develop an equation that relates the rms voltage of a sine wave to its peak-to-peak voltage. a. If a sine wave has a peak-to
Aleks04 [339]

Answer:

(A) Equation will be v=v_msin\omega t=0.75sin(18840t)

(B) RMS value of voltage will be 0.530 volt

Explanation:

We have given peak to peak voltage of ac wave = 1.5 volt

Peak to peak voltage of ac wave is equal to 2 times of peak voltage

So 2v_{peak}=1.5volt

v_{peak}=\frac{1.5}{2}=0.75volt

Frequency of ac wave is given f = 3 kHz

So angular frequency \omega =2\pi f = 2×3.14×3000 = 18840 rad/sec

So expression of equation will be v=v_msin\omega t=0.75sin(18840t) ( As phase difference is 0 )

Now we have to find the rms value of voltage

So rms voltage will be equal to v_{rms}=\frac{v_{peak}}{\sqrt{2}}=\frac{0.75}{1.414}=0.530volt

4 0
3 years ago
A 500 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exert
liberstina [14]

Answer:

x = 7.62 m

Explanation:

First we need to calculate the weight of the rocket:

W  = mg

we will use the gravity as 9.8 m/s². We have the mass (500 g or 0.5 kg) so the weight is:  

W  = 0.5 * 9.8 = 4.9 N

We know that the rocket exerts a force of 8 N. And from that force, we also know that the Weight is exerting a force of 4.9. From here, we can calculate the acceleration of the rocket:

F - W = m*a

a = F - W/m

Solving for a:

a = (8 - 4.9) / 0.5

a = 6.2 m/s²

As the rocket is accelerating in an upward direction, we can calculate the distance it reached, assuming that the innitial speed of the rocket is 0. so, using the following expression we will calculate the time which the rocket took to blast off:            

y = vo*t + 1/2 at²

y = 1/2at²

Solving for t:

t = √2y/a

t = √2 * 20 / 6.2

t = √6.45 = 2.54 s

Now that we have the time, we can calculate the horizontal distance:

x = V*t

Solving for x:

x = 3 * 2.54 = 7.62 m            

4 0
4 years ago
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