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zysi [14]
3 years ago
7

During a visit to the beach, you get in a small rubber raft and paddle out beyond the surf zone. Tiring, you stop and take a res

t. Describe the movement of your raft during your rest. How does this movement differ, if at all, from what you would have experienced if you had stopped paddling while in the surf zone?
Physics
1 answer:
Monica [59]3 years ago
3 0

Answer:

The main difference in these two movements is that the first is a pure swing movement and the followed form a wave travels from the beach

Explanation:

The movement in the two parts is very different, when the surf zone has passed it is in a deeper part of the water where the seabed does not rise much, therefore due to the movement of the waves there is an upward oscillatory movement and descending, in this movement there is no horizontal displacement.

When it is within the southern zone, there is a rapid rise of the sea floor, which generates a horizontal movement, having a traveling wave, therefore your movement is more complicated, you can have some oscillating movement on the axis and, but in addition to this you have a horizontal movement that reaches you towards the beach, forming a Traveling wave.

The main difference in these two movements is that the first is a pure swing movement and the followed form a wave travels from the beach

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A ball whose mass is 1.9 kg is suspended from a spring whose stiffness is 8.0 N/m. The ball oscillates up and down with an ampli
MArishka [77]

Answer:

2.05 radians/s

Explanation:

This is a simple harmonic motion. The angular frequency of a loaded spring is given by

\omega = \sqrt{\dfrac{k}{m}}

where k is the spring constant and m is the mass on the spring.

Using the known values,

\omega = \sqrt{\dfrac{8}{1.9}} = 2.05

4 0
3 years ago
An apple falls out of a tree from a height of 2.3m. what is the impact speed of the apple
Anuta_ua [19.1K]

Answer:6.71 m/s

Explanation:

Given

Apple fall from a height of h=2.3 m  

We need to find the impact speed of apple which can be given by using

v^2-u^2=2gh  

where v=final velocity

u=initial velocity

h=Displacement

Assuming initial velocity to be zero

substituting the value we get

v^2-0=2\times 9.8\times 2.3  

v=\sqrt{2\times 9.8\times 2.3}  

v=6.71\ m/s  

5 0
3 years ago
Difference between incident ray and reflected ray​
SSSSS [86.1K]

Answer:

An incident ray is a ray of light that strikes a surface. The angle between this ray and the perpendicular or normal to the surface is the angle of incidence.

The reflected ray corresponding to a given incident ray, is the ray that represents the light reflected by the surface. The angle between the surface normal and the reflected ray is known as the angle of reflection. The Law of Reflection says that for a specular (non-scattering) surface, the angle of reflection always equals the angle of incidence.

3 0
3 years ago
help me solve this: a bicyclist in the tour de france crests a mountain pass as he moves at 18 km/h. At the bottom, 4.0 km farth
Lana71 [14]
First we have to convert:
75 km / h ( * 3.6 ) = 270 m/s
18 m/s = 64.8 m/s
d = v i · t + 1/2 a · t²
v = v i + a t
-----------------------------------
4000 = 64.8 · t + 1/2 a · t²
270 = 64.8 + a t
a = ( 270 - 64.8 ) / t
a = 205.2 / t
4000 = 64.8 t + 1/2 · ( 205.2 / t ) · t²
4000 = 64.8 t + 102.6 t
4000 = 167.4 t
t = 4000 : 167.4 = 23.89 s
a = 205.2 : 23.89 = 8.58 m/s²
Answer: His average acceleration was 8.58 m/s²

7 0
3 years ago
10)A car is moving from rest and attained a velocity of 80 m/s. Calculate the
Mashcka [7]

Explanation:

the velocity graph of a ball mass 20mg moving along a straight line

5 0
4 years ago
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