The height of the triangle if the base is 8 is 3.96 units
Given the following parameters
Base of a triangle = 8 units
Let the hypotenuse be "c"
Let the height be "h"
If the length of the hypotenuse of a right triangle is one unit more than twice the height, then;
c = 2h + 1
According to the Pythagoras theorem:
c² = b² + h²
(2h + 1)² = 8² + h²
Expand
4h²+4h+1 = 64 + h²
4h²-h² + 4h + 1 - 64 = 0
3h² + 4h - 63 = 0
Factorize the result
On factorizing, the value of the height is 2
h = 
h = 11.89/3
h = 3.96 units
Hence the height of the triangle if the base is 8 is 3.96 units
Learn more here: brainly.com/question/20545047
Answer:
3ac-a+2b
a=2,b=1,c=4
Step-by-step explanation:
3*2*4-2+2*1
24-2+2=24
Answer:
21
Step-by-step explanation:
20 x 10 = 200 so 20 students sleep for 9 hours
that leaves 10
since 10 is half of 20, half of 2 is 1 so that last 10 = 1 student,
making 21 students
3/8 is equivalent to 0.375.
Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°