So if you want to find the answer you would find it by doing it yourself
Answer:
Relative Frequency Method
Step-by-step explanation:
If I carry out an experiment involving 25 throws of a coin and I obtain 13 Heads(H), the Relative Frequency of obtaining Heads will be 13/25.
Now if I intend to find out approximately how many Heads will
occur in 300 throws, I simply use the result or experimentation data that I have.
This is done below:
Relative Frequency of Obtaining a Head= 13/25 =0.52
Number of Heads obtained in 300 throws
= Relative Frequency X Number of Trials
=0.52 X 300
=156
This is an example of how relative frequency method works.
1.

2. -2+5n or 5n-2
3. (12s)+150 where s=number of students
4. 3(32)+1(53)=96+53=159 per hour, so 159h
9. √105 is irrational, -4 is an integer, 4/3 is a rational number, order is -4,3/4, √105
10. 3²=9, 4²=16, so between 3 and 4, but closer to 4, so √14≈4
11. that is the associative property, it deals with moving parentahees around
12. 2(6.25)+1(5.50)+2(2.75)=2(6.25+2.75)+1(5.50)=2(9)+5.5=18+5.5=23.5
13. yes, because they are both 2 less than 3 times of a number
14. maybe 18 times 3, so (4²+2) times 3=54
Answer:
0.0159
Step-by-step explanation:
Given that a common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, because customers who buy tickets do not always show up for the flight.
Here if X is the no of persons that do not show up, then X is binomial as each trial is independent with p = 0.04 and n =150 (no of tickets sold)
The plane is overbooked if more than 150 show up
i.e. less than 2 do not show up
Hence the probability that the airline overbooked this flight
=