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sertanlavr [38]

2 years ago

9

Find the slope using points ( 4 , 0 ) and ( 12, 2) Will give brainliest to best answer

1 answer:

dolphi86 [110]2 years ago

8 0

Slope = (y2-y1)/(x2-x1) = (2-0)/(12-4) = 2/8 = 1/4

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Leto [7]

Answer:

C

Step-by-step explanation:

3 0

2 years ago

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21. Randy owns a computer store. In 1990, he sold 150 monitors. In 2000, he sold 900

lutik1710 [3]

Answer:

$y=75x+150$

Step-by-step explanation:

Let $y$ represent the number of monitors sold.

Given:

$x$ is the number of years since 1990.

So, for the year 1990, $x=0$ .

For the year 2000, 10 years passed. So, $x=10$ .

Now, monitors sold in 1990 are 150. So, at $x=0,y=150$

Monitors sold in 2000 are 900. So, at $x=10,y=900$

Thus, the two points are $(0,150)$ and $(10,900)$ .

The slope of a line with points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

Slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

For the points $(0,150)$ and $(10,900)$ , the slope is given as:

Slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\ m=\frac{900-150}{10-0}\\ m=75$

Now, the y-intercept is the point where $x=0$ . So, the point $(0,150)$ has $x$ value as 0.

So, the y-intercept is 150.

Equation of a line in slope-intercept form is given as:

$y=mx+b$

Where, $m$ is the slope and $b$ is the y intercept.

Here, $m=75$ and $b=150$ .

Therefore, the equation that represents the above data is given as:

$y=75x+150$

7 0

2 years ago

What can be concluded about the relationship between the two functions?

alisha [4.7K]

<span>Both variables are categorical. We analyze an association through a comparison of conditional probabilities and graphically represent the data using contingency tables. Examples of categorical variables are gender and class standing.</span>

5 0

2 years ago

Whats 9+10?<br><br> A. 21<br> B. 19

Airida [17]

Answer:

LOL it's 19 what grade are you in?

6 0

3 years ago

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Random samples of size 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively.

TiliK225 [7]

Answer:

d. 200 and 2

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

Mean = 200

Standard deviation = 18

Sample size: 81

Standard error: $s = \frac{18}{\sqrt{81}} = 2$

So the correct answer is:

d. 200 and 2

7 0

3 years ago

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