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dlinn [17]
2 years ago
11

" title="4 - \frac{2}{3}x = \frac{x - 6}{5} " alt="4 - \frac{2}{3}x = \frac{x - 6}{5} " align="absmiddle" class="latex-formula">
x=? Please tell​
Mathematics
1 answer:
morpeh [17]2 years ago
7 0
4-2/3x=x-6/5

Answer: X=6
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Adjacent angles whose exterior sides are opposite rays are _______ a0.
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They are complementary
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Find the solution to the system of equations y=−7x+3y=−x−3​
babunello [35]

Answer:

x=1, y=-4. (1, -4).

Step-by-step explanation:

y=-7x+3

y=-x-3

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-7x+3=-x-3

-7x-(-x)+3=-3

-7x+x=-3-3

-6x=-6

6x=6

x=6/6

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y=-1-3=-4

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Really need big help on this one please
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Answer:

Answer equals to 55.75ftsquare

Step-by-step explanation:

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In a video game, Charles scored -250 points on his second play this brought his total score to 500. What was his score on the fi
Lyrx [107]
His First Play Was 750 Points

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4 0
3 years ago
Read 2 more answers
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
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