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3 years ago

12

an airplane is cruising at an altitude of 40000 feet begins at a distant to land it loses altitude at a rate of 1500 feet per mi

nute how long will it take to reach the ground?

1 answer:

Lemur [1.5K]3 years ago

7 0

27.7-. or is it something else?!?!?

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Answer:

$31\frac{1}{5}\ miles$

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

so

The distance is equal to multiply the speed by the time

we have

$speed=9\frac{3}{5}\ \frac{miles}{hour}$

$time=3\frac{1}{4}\ hours$

$distance=(9\frac{3}{5})(3\frac{1}{4})$

Convert mixed number to an improper fraction

$9\frac{3}{5}=9+\frac{3}{5}=\frac{9*5+3}{5}=\frac{48}{5}$

$3\frac{1}{4}=3+\frac{1}{4}=\frac{3*4+1}{4}=\frac{13}{4}$

substitute

$distance=(\frac{48}{5})(\frac{13}{4})=\frac{624}{20}=31,2\ miles$

Convert to mixed number

$31.2\ mi=31+0.2=31+\frac{1}{5}=31\frac{1}{5}\ miles$

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