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Olin [163]
3 years ago
12

an airplane is cruising at an altitude of 40000 feet begins at a distant to land it loses altitude at a rate of 1500 feet per mi

nute how long will it take to reach the ground?
Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0
27.7-. or is it something else?!?!?
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Which is a composite number A. 81 B. 41 C. 61 D. 71
UNO [17]
A,81 because if you try checking 81 will be the only composite number im in 6 grade.....

6 0
3 years ago
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Which expression is modeled by this arrangement of tiles? 40 positive tiles are broken up into 10 groups of 4 positive tiles. 40
Lisa [10]

Answer:

\frac{40}{4}

Step-by-step explanation:

The model shows that there are 40 tiles which were divided into 4 per group. This results into 10 groups. That is:

\frac{40 tiles}{4} = 10 groups

Therefore, the expression modeled by the arrangement of the tiles is \frac{40}{4}

6 0
3 years ago
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There were 90 runners just start a race in the first half of the race 1/3 of them dropped out in the second half of the race 1/5
Eva8 [605]

Answer:

6 runners finished the race

Step-by-step explanation:

it starts with 90 runners. then 1/3 of them dropped out in the second half of the race, that means you do 90 divided by 3

90 ÷ 3 = 30

Then, 1/5 of the runners remained.

That means you do 30 divided by 5

30÷ 5= 6

so the answer is 6 remaining runners finished the race.

8 0
3 years ago
Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

4 0
3 years ago
What is the LCD for the given equation?
velikii [3]

Answer:

(x-3)^2

Step-by-step explanation:

The LCD is (x-3)^2 This is becuse x-3 is on both equations.  


5 0
3 years ago
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