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MrRa [10]
3 years ago
7

What are the three choices equivalent to 27^4/3

Mathematics
1 answer:
12345 [234]3 years ago
8 0

the answers are B,D and F

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Correct/best answer will get brainliest!
vodka [1.7K]
The answer would be b.100 because its clearly not a right triangle
6 0
3 years ago
The manager at a supermarket arranged 10 rows of cans. He put 2 cans in the first row, 4 cans in the second row, and 6 cans in t
Elena-2011 [213]
A)

2, 4, 6, 8, *10

The fifth row contains 10 cans.

----------------------------------------------------

b)

2+4+6+8+10+12+14+16+18+20=110

-----------------------------------------------------

c)
 
2*Row=Number Of Cans

When Row=1, Number Of Cans=2.

When Row=5, Number Of Cans=10.

When Row=10, Number Of Cans=20.
6 0
3 years ago
Help please?
Alla [95]
\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}

\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k
6 0
3 years ago
Write the domain and range as an inequality please!!!<br> 
Nat2105 [25]

Answer:

x > -1

Step-by-step explanation:

Domain is the set of x-values that can be inputted into function f(x).

From the graph we can see that our x-values span from -1 to infinity. Since -1 is open dot, it is not included in the domain:

(-1, ∞) or x > -1

5 0
3 years ago
3-2i/1+4i include each step necessary in simplifying
Likurg_2 [28]

Answer:

\frac{3-2i}{1+4i}=\frac{11}{17}-\frac{10}{17}i

Step-by-step explanation:

\frac{3-2i}{1+4i} <-- Given

\frac{3-2i}{1+4i}*\frac{1-4i}{1-4i} <-- Multiply by the conjugate of the denominator as a factor of 1

\frac{(3-2i)(1-4i)}{(1+4i)(1-4i)}

\frac{(3)(1)+3(-4i)-2i(1)-2i(4i)}{(1)(1)+1(-4i)+4i(1)+4i(-4i)} <-- Use the Distributive Property and FOIL

\frac{3-12i-2i-8i^2}{1-4i+4i-16i^2}

\frac{3-10i-8i^2}{1-16i^2}

\frac{3-10i-8(-1)}{1-16(-1)} <-- Rewrite i^2 as -1

\frac{3-10i+8}{1+16}

\frac{11-10i}{17}

\frac{11}{17}-\frac{10}{17}i <-- Rewrite in a\pm bi form

8 0
3 years ago
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