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2 years ago

7y+3=3x+11 find x and y

Mathematics

1 answer:

kvasek [131]2 years ago

5 0

Answer:

7y + 3 = 3x + 11

7y = 3x + 11 - 3

7y = 3x + 8

y = 3x + 8 / 7

7y + 3 = 3x + 11

7y + 3 - 11 = 3x

7y - 8 = 3x

x = 7y - 8 / 3

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Lastima Nelson, Inc. is recruiting a new Chief Financial Officer (CFO). The recruiting budget is $44,000. Lastima has spent $10,

Musya8 [376]

The budget is $44000

Total spent so far is $10000 + $8500 = $18500

The amount left to spend = 44000 - 18500 = $25500

$25500 is the maximum 6% commission that Lastima Nelson Inc. can spend and stays within the budget

Let the maximum price of the home be $x$
This value of $x$ will be the 100% before the 6% commission is calculated of it.

6% of $x$ is 25500
1% of $x$ is 25500 ÷ 6 = $4250
100% of $x$ is 4250 × 100 = $425,000

So, the maximum value of the home is $425,000

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3 years ago

Can someone solve this

valentinak56 [21]

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2 years ago

I don’t understand. online school is hard

Minchanka [31]

I think you got to multiply the numbers hopefully I helped

5 0

3 years ago

Read 2 more answers

1 and 3/4 times 1 and 1/3

Orlov [11]

Answer:

7/3

Step-by-step explanation:

Simplify the following:

(1 + 3/4) (1 + 1/3)

Hint: | Put the fractions in 1 + 1/3 over a common denominator.

Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:

(1 + 3/4) 3/3 + 1/3

Hint: | Add the fractions over a common denominator to a single fraction.

3/3 + 1/3 = (3 + 1)/3:

(1 + 3/4) (3 + 1)/3

Hint: | Evaluate 3 + 1.

3 + 1 = 4:

(1 + 3/4)×4/3

Hint: | Put the fractions in 1 + 3/4 over a common denominator.

Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:

4/3 4/4 + 3/4

Hint: | Add the fractions over a common denominator to a single fraction.

4/4 + 3/4 = (4 + 3)/4:

4/3 (4 + 3)/4

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

7/4×4/3

Hint: | Express 7/4×4/3 as a single fraction.

7/4×4/3 = (7×4)/(4×3):

(7×4)/(4×3)

Hint: | Cancel common terms in the numerator and denominator of (7×4)/(4×3).

(7×4)/(4×3) = 4/4×7/3 = 7/3:

Answer: 7/3

8 0

3 years ago

Read 2 more answers

The average rate of job submissions in a busy computer center is 3 per minute. If it can be assumed that the number of submissio

san4es73 [151]

The probability that at least 40 jobs will be submitted in 15 minutes is 0.79162.

The number of jobs submitted per minute follows Poisson Distribution.

A Poisson Distribution over a variable X, having a mean λ, has a probability for a random variable x as $P(X= x) = e^{-\lambda} \frac{\lambda^{x} }{x!}$ .

In the question, we have the random variable x = 40.

The mean λ = Average jobs per minute*time = 3*15 = 45.

We are to find the probability that at least 40 jobs will be submitted in 15 minutes, which is represented as P(X ≥ 40) = P(X > 39).

P(X > 39) = 1 - P(X ≤ 39) = 1 - poissoncdf(45,39)

As to find the probability of a Poisson Distribution P(X ≤ x), for a mean = λ, we use the calculator function poissoncdf(λ,x).

Therefore, P(X > 39) = 1 - 0.20838 = 0.79162.

Therefore, the probability that at least 40 jobs will be submitted in 15 minutes is 0.79162.

Learn more about the Poisson Distribution at

brainly.com/question/7879375

#SPJ4

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2 years ago