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FromTheMoon [43]

3 years ago

10

Ociel has designed a square mural that measures 10 feet on each side. Bill has also designed a square mural, but his measures y

feet shorter on each side. How much smaller than Ociel's mural is Bill's mural? Explain

1 answer:

Papessa [141]3 years ago

5 0

Ocel’s 10x10=100
Bill’s (10 - y) (10 - y)

I don’t know which answer your teacher wants
100 - [(10-y)(10-y)]
100 - (100 -20y + y^2}
20y - y^2

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12 problems in45 mins 20 problems in how much time

Anni [7]

Answer:

75 mins or 1 hour 15 min :)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which is greater 3/7 3/6 3/5

Elanso [62]

3/7= 0.428571

3/6= 0.5

3/5= 0.6

So 3/5 is the greatest of all of them.

8 0

3 years ago

Read 2 more answers

matrenka [14]

Answer:

$y = -\frac{3}{2}x+15$

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

$y = \frac{2}{3}x$

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

$y = \frac{2}{3}x$

Now, we compare the given equation by standard form $y = mx +c$

So, slope of the line $m_{1} = \frac{2}{3}$ , and

y-intercept $c=0$

We know that the slope of the perpendicular line $m_{1}\times m_{2} = -1$

$m_{2}=-\frac{1}{m_{1}}$

$m_{2}=-\frac{1}{\frac{2}{3} }$

$m_{2}=-\frac{3}{2}$

So, the slope of the perpendicular line $m_{2}=-\frac{3}{2}$

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

$y=mx+c$

Substitute point $P(x_{1}, y_{1})=P(6, 6)$ and $m = m_{2}=-\frac{3}{2}$

$6=-\frac{3}{2}\times 6 +c$

$6=-3\times 3 +c$

$c=6+9$

$c=15$

So, the y-intercept of the perpendicular line $c=15$

Using point slope formula.

$y=mx+c$

Substitute $m = m_{2}=-\frac{3}{2}$ and $c=15$ in above equation.

$y = -\frac{3}{2}x+15$

Therefore: the equation of the perpendicular line $y = -\frac{3}{2}x+15$

8 0

3 years ago

Angel and Jayden were at track practice. The track is 2/5 kilometers around.  Angel ran 1 lap in 2 minutes.  Jayden ran 3 laps

choli [55]

Answer:

6/25 km in 1 min; or 0.24 km/min

Step-by-step explanation:

The info about Angel is not necessary.

Jayden runs 3 laps in 5 mins

Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.

Distance = rate x time

6/5 km = rate (5 min)

We want to isolate r (rate), so divide both sides by 5 min

6/5 km ÷ 5 min = r

6/5 km (1/5 min) = r

6/25 km/min = r (notice how the units worked out correctly to km/min)

So, Jayden runs 6/25 km in 1 min.

7 0

2 years ago

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A park has a length to width ratio of 7:4 and the perimeter of the park is 880 meters. What are the length and width of the park

Schach [20]

Step-by-step explanation:

Ratio of length to width = 7 : 4

length = 7x

width = 4x

7x + 4x = 11x

length = 880

$880 + 4x = 11x$

$880 = 11x - 4x$

$880 = 7x$

$\frac{880}{7} = x$

$125.71 = x$

width = 4x

= 4(125.71)

= 502.85

3 0

2 years ago