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3 years ago

Using the variable c for the unknown number what is the sum of 5 times a number and 9 is equal to 6

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

6 0

$5c + 9 = 6 \\$
$5c = 6 - 9 \\$
$5c = - 3$
$c = - 3 \div 5 \\ c = - \frac{3}{5}$

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Boys competing in the long jump event must jump at least 15 feet to qualify for the state track and field

Helen [10]

<h3>Answers: C) 4.5 m, D) 3.92 m, E) 3.5 m</h3>

Work Shown:

Convert from feet to meters.

15 feet = (15 ft)*(0.3048 m/1 ft)

15 feet = (15*0.3048) meters

15 feet = 4.572 meters approximately

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3 years ago

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3 years ago

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Tpy6a [65]

Answer:

5 weeks

Step-by-step explanation:

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4 years ago

Use the completing the square method to find the roots of 2x^2+3x-15=13 include the steps, it would be greatly appreciated thank

Monica [59]

Answer:

The roots are

$x1= \frac{-3+\sqrt{233}}{4}$

$x2= \frac{-3-\sqrt{233}}{4}$

Step-by-step explanation:

we have

$2x^{2}+3x-15=13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$2x^{2}+3x=13+15$

$2x^{2}+3x=28$

Factor the leading coefficient

$2(x^{2}+(3/2)x)=28$

Complete the square. Remember to balance the equation by adding the same constants to each side

$2(x^{2}+(3/2)x+(9/16))=28+(9/8)$

$2(x^{2}+(3/2)x+(9/16))=233/8$

$(x^{2}+(3/2)x+(9/16))=233/16$

Rewrite as perfect squares

$(x+(3/4))^{2}=233/16$

square root both sides

$(x+\frac{3}{4})=(+/-)\sqrt{\frac{233}{16}}\\ \\(x+\frac{3}{4})=(+/-)\frac{\sqrt{233}}{4}\\ \\x= -\frac{3}{4}(+/-)\frac{\sqrt{233}}{4}$

$x1= -\frac{3}{4}(+)\frac{\sqrt{233}}{4}=\frac{-3+\sqrt{233}}{4}$

$x2= -\frac{3}{4}(-)\frac{\sqrt{233}}{4}=\frac{-3-\sqrt{233}}{4}$

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3 years ago