Calculate the followingA)-10-(-19)+(8-16)B)-6×2+4÷2
2 answers:
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Answer:
(x,y) = Any point on the line
m = the slope of the line
(x₁, y₁) = A given point on the line
Step-by-step explanation:
the equation of a straight line is;
y = mx + c
where;
x and y are any point on the line
m is the slope of the line
c is the intercept on the y axis
And a given point on (x,y) can be written as (x₁, y₁)
Therefore, for the case above;
(x,y) = Any point on the line
m = the slope of the line
(x₁, y₁) = A given point on the line
Answer:
- see the attachment
- (x, y) = (1, 1)
Step-by-step explanation:
1. Since you have y > ..., the boundary line is dashed and the shading is above it (for y-values greater than the values on the line). The boundary line is ...
y = 2x+3
which has a y-intercept of 3 and a slope (rise/run) of 2. A graph is attached.
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2. You can add the two equations to eliminate y:
(3x +y) +(x -y) = (4) +(0)
4x = 4
x = 1
1 - y = 0 . . . . substitute into the the second equation
1 = y . . . . . . . add y
The solution is (x, y) = (1, 1).
