(1/5) times (the relay) = 3/4 mile
Multiply each side by 5
The relay = (5) x (3/4) = 15/4 = <span>3.75 miles.</span>
Step-by-step explanation:
so, I assume the patio is a true rectangle.
the area of a rectangle is
length × width
in our case that means
1.3 = 5 × width
width = 1.3 / 5 = 0.26 ft
so, this is just a very narrow strip of 0.26ft × 5 ft.
I would not call that a patio ...
or was it a typo, and the area is actually 30 ft² ?
then we would have
30 = 5 × width
width = 30 / 5 = 6 ft
C. Acute vertically opposite angles
Answer:
bruuuuuuuuuh idek that HOOOOOOOOW wut is that?!?!
Step-by-step explanation:
Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)