Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k
we have some points
(3,-2) and (6,-26)
input and solve for a and k
(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k
(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k
we have
-2=a+k
-26=4a+k
multiply first equation by -1 and add to second
2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k
-24=3a
divide both sides by 3
-8=a
-2=a+k
-2=-8+k
add 8 to both sides
6=k
the equation is
Answer:
three sides measuring 4 ft, 8 ft, and 10 ft
Step-by-step explanation:
To choose which dimensions that can create more than one triangle, we consider the given values carefully and how possible it will be to construct.
The only dimensions given in the option that will be possible to create more than one triangle from it, is three sides measuring 4 ft, 8 ft, and 10 ft.
4 ft, 8 ft, and 10 ft are in simple multiple of 2
4 ft, 8 ft, and 10 ft = 2 (2 ft, 4 ft, and 5 ft ), with this we can construct two triangles with three sides measuring 2 ft, 4 ft, and 5 ft.
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Step-by-step explanation: