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3 years ago

Using the pattern learned for the perfect squares, what is the product?

Mathematics

1 answer:

anyanavicka [17]3 years ago

3 0

Answer:

9x^2-30xy^2+25y^4

Step-by-step explanation:

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Calculate the semi-interquartile range of the data shown 21; 34; 53, 43; 27; 38; 20; 32; 13;42:55

yKpoI14uk [10]

Answer:

21yrnrndjen edjdje ebsjnednzhdhr

4 0

3 years ago

Guys please help with this question thanks

erastova [34]

= 16 + 49 - 3(11) - 4(10)
= 16 + 49 - 33 - 40
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3 0

3 years ago

A class of girls to boys is 5:3. If there are 9 boys, how many girls are in this class

Wewaii [24]

Answer:

15 girls

Step-by-step explanation:

Girls : Boys

5 3

To get to 9 boys multiply by 3

Girls : Boys

5*3 3*3

15 9

There are 15 girls

5 0

3 years ago

Find the sum or difference.

Schach [20]

C is the correct one

7 0

3 years ago

Read 2 more answers

What’s the differential equation of

worty [1.4K]

Answer:

$y=\frac{1}{x^{2}-6x+13 }$

Step-by-step explanation:

We have given,

$\frac{dy}{dx}=y^{2}(6-2x)$

and initial condition $x=3,\ y=\frac{1}{4}$

Now,

$\frac{dy}{dx}=y^{2}(6-2x)$

Rearranging the variables, we get

$\frac{dy}{y^{2} }=(6-2x).dx$

Applying integration both sides, we get

$\int\ {\frac{dy}{y^{2} } } \,=\int\ {(6-2x).} \, dx$

⇒ $\frac{-1}{y} =6x-\frac{2x^{2} }{2}$

⇒ $\frac{-1}{y}=6x-x^{2} +C$

Putting the initial condition (i.e., $x=3,\ y=\frac{1}{4}$ ), we get

⇒ $-4=6\times3-(3)^{2}+C$

⇒ $-4=18-9+C$

∴ $C=-13$

We have, $\frac{-1}{y}=6x-x^{2} +C$

now putting the value of $C$ in above equation, we get

⇒ $\frac{-1}{y}=6x-x^{2} -13$

⇒ $\frac{1}{y}=-6x+x^{2} +13$

$y=\frac{1}{x^{2}-6x+13 }$

5 0

3 years ago