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TiliK225 [7]
3 years ago
9

A pack of cinnamon-scented pencils sells for $4.00. What is the sales tax rate if the total cost of the total cost of the pencil

s is $4.32?
Mathematics
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer:

6%

Step-by-step explanation:

den301095 [7]3 years ago
4 0

Answer:

6%

Step-by-step explanation:

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Contact [7]
<span>Given: C -> Umesh's total charge in dollars. h -> the number of hours he spends on a job. Hourly charge =$80 /hr Charge for h hours = 80*h fixed charge per job = $50 Therefore, C = 80h +50 is the required equation to find the total charges</span>
8 0
3 years ago
What is the total surface area??
Olenka [21]

Answer:

216

Step-by-step explanation:

Use geometric formulas to solve for each individual SIDE of the triangular prism

TOP and BOTTOM TRIANGLE sides:

  • \frac{ab}{2}
  • \frac{6(8)}{2}  <--- times 2 because we have TWO identical triangle sides

RIGHT RECTANGULAR side from our perpsective:

  • LxW
  • 8(7)

FRONT RECTANGULAR side:

  • LxW
  • 7(6)

BACK RECTANGULAR side:

  • LxW
  • 7(10)

Now you add all of those formulas together for your answer.

\frac{6(8)}{2} + \frac{6(8)}{2} + 8(7)  + 7(10) + 7(6)

= 216

4 0
3 years ago
You put 60% of your paycheck into your savings account. Your paycheck is $235. How much money do you put in your savings account
KIM [24]
$141

$235 x 0.60 = $141
8 0
3 years ago
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Can you help me please?
kirza4 [7]
23 1/3 or 23.3 is your answer .-.
3 0
3 years ago
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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
Read 2 more answers
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