The surface area of a prism:
2 times the area of the base + perimeter of the base multiplied by the height.
AKA:
2 x area of base + perimeter of the base x height
Xxx :)
A (4,8) and b (7,2) and let c (x,y)
A , B and C are col-linear ⇒⇒⇒ ∴ slope of AB = slope of BC
slope of AB = (2-8)/(7-4) = -2
slope of BC = (y-2)/(x-7)
∴ (y-2)/(x-7) = -2
∴ (y-2) = -2 (x-7) ⇒⇒⇒ equation (1)
<span>The distance
between two points (x₁,y₁),(x₂,y₂) = d
</span>
The ratio of AB : BC = 3:2
AB/BC = 3/2
∴ 2 AB = 3 BC

= <span>

eliminating the roots by squaring the two side and simplifying the equation
∴ 4 * 45 = (x-7)² + (y-2)² ⇒⇒⇒ equation (2)
substitute by (y-2) from equation (1) at </span><span>equation (2)
4 * 45 = 5 (x-7)²
solve for x
∴ x = 9 or x = 5
∴ y = -2 or y = 6
The point will be (9,-2) or (5,6)
the point (5,6) will be rejected because it is between A and B
So, the point C = (9,-2)
See the attached figure for more explanations
</span>
First you subtract 7 minus 19 and 7/8b minus 5/4b:
5/4b+7=7/8b+19
-7/8b -7/8b
5/4b+7=7/8b+19
-7 -7
3/8b=12
Then you divide 12 by 3/8:
b=32
<span>Quadratic because you have x^2</span>